Solution:- Given numbers to compare are 512 and 521 .
As they are 3 digit numbers
So, we have to compare hundreds place.
But hundreds are equal in both the numbers with digit 5.
Next we have to compare tens place.
Case 1 :- 1 ten is smaller in 512 than 2 tens in 521 .
So we get the result that,
512 is smaller than 521
or <em> 512 < 521</em>
Case 2:-2 tens is greater in 521 than 1 ten in 512 .
So we get the result that,
521 is greater than 512
or <em> 521 > 512</em>
<span>The one-way ANOVA or one – way analysis of
variance is used to know whether there are statistically substantial
dissimilarities among the averages of three or more independent sets. It
compares the means between the sets that is being examined whether any of those
means are statistically pointedly dissimilar from each other. If it does have a
significant result, then the alternative hypothesis can be accepted and that
would mean that two sets are pointedly different from each other. The symbol, ∑
is a summation sign that drills us to sum the elements of a sequence. The
variable of summation is represented by an index that is placed under the
summation sign and is often embodied by i. The index is always equal to 1 and
adopt values beginning with the value on the right hand side of the equation
and finishing it with the value over head the summation sign.</span>
Answer:
There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.
Decision rule: Reject the null hypothesis if (P-value < level of significance)
Test statistic z=-2.70
Decision: Reject the null hypothesis (0.003<0.010)
Step-by-step explanation:
In this question we have to test an hypothesis.
The null and alternative hypothesis are:
The significance level is assumed to be 0.01.
The sample of size n=80 gives a proportion of p=61/80=0.7625.
The standard deviation is:
The statistic z is then
The P-value is
The P-value (0.003) is smaller than the significance level (0.010), so the effect is significant. The null hypothesis is rejected.
There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.
Decision rule: Reject the null hypothesis if (P-value < level of significance)
Test statistic z=-2.70
Decision: Reject the null hypothesis (0.003<0.010)
Given: line segment AB // to line segment CD, ∠B ≅∠D and line segment BF ≅ to line segment ED. Prove: Δ ABF ≅ Δ CED.
Follow the matching numbers on the statement versus reason chart.
Statement:
1. line segment AB // to line segment CD.
2. ∠B ≅∠D
3. line segment BF ≅ to line segment ED.
4. ∠A ≅∠C
5. Δ ABF ≅ Δ CED
Reason:
1. Given
2. Given
3. Given
4. Alternate interior angles are congruent.
5. Corresponding parts of congruent triangles are congruent.
Answer:
O y > 4
Step-by-step explanation:
The dotted line indicates the line is not part of the inequality, and it is clearly greater than 4.