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1 year ago

A=sina-cosa B=sina+cosa proved A+1/B-1=1+sina/cosa

Mathematics

1 answer:

MA_775_DIABLO [31]1 year ago

5 0

Answer: mbakslot situs gacor

Step-by-step explanation:

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Find y (please someone answer)

Alex73 [517]

Answer:

Y=√2

Step-by-step explanation:

We can use the pathagorian theorum: A²+B²=C² now in this case it would be X²+Y²=2² we also know that X and Y are the same number in this problem because they have the same corresponding angle (triangle angles always add to 180 and since we know 2 of the angles are 45 and 90 the remaining angle will also be 45) Because of this we can change our equation to Z²+Z²=2² (I'm using Z so that we do not confuse it with another letter we've already used) from there we can go to Z∧4=2² and then we will solve the equation. Z=√2 Z also equals X and Y therefore Y=√2

I hope this helps and please let me know if there is anything you don't understand I would be happy to clarify!

5 0

2 years ago

Thanks if you help.....

marissa [1.9K]

Answer:

I'm guessing it's D.

Step-by-step explanation:

Sorry if wrong :> Hope i helped! Have a awesome day!!! You're a great hooman ^_^ Please mark brainliest !!

5 0

2 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

2 years ago

GET 20 PTS AND BE NAMED BRAINLIEST AND GET A THANK U AND A FOLLOW

insens350 [35]

<h3>Therefore 24 students take a car to school. </h3>

Step-by-step explanation:

Given, Total number of students is 80.

and 30% of the total students take a car to school

30% of 80

$=\frac{30}{100}\times 80$

=24

Therefore 24 students take a car to school.

3 0

2 years ago

HELP!! I NEED THIS QUICKLY

Elza [17]

Answer:

A and D

Step-by-step explanation:

We are given that

(3/4,2/3),(1/4,1),(1,1/2) and (1/2,1)

$x_1=\frac{3}{4}$

$y_1=\frac{2}{3}$

$x_2=\frac{1}{4},y_2=1$

$x_3=1,y_3=\frac{1}{2}$

$x_4=\frac{1}{2},y_4=1$

k= $\frac{1}{2}$

Direct proportion:

$\frac{x}{y}=k$

Inverse proportion: $xy=k$

$\frac{x_1}{y_1}=\frac{3}{4}\times \frac{3}{2}=\frac{9}{8}\neq \frac{1}{2}$

Therefore, it is not in direct proportion.

$\frac{1}{4\times 2}=\frac{1}{8}\neq\frac{1}{2}$

$\frac{1}{\frac{1}{2}}=2\neq \frac{1}{2}$

$x_1y_1=\frac{3}{4}\times \frac{2}{3}=\frac{1}{2}$

$x_2y_2=\frac{1}{4}\times 2=\frac{1}{2}$

$x_3y_3=1\times \frac{1}{2}=\frac{1}{2}$

$x_4y_4=\frac{1}{2}\times 1=\frac{1}{2}$

Therefore, $xy=k=\frac{1}{2}$

Hence, the given points form an inverse variation .

$xy=\frac{1}{2}$

$y=\frac{1}{2x}$

Option A and D is true.

6 0

2 years ago