Answer:

Step-by-step explanation:
Given that,
The height of a cell tower, P = 70 m
The tower casts a shadow of 45 meters on the ground.
We need to find the angle of elevation of the shadow to the top of the cell tower. We can use trigonometry to find it.

Put all the values,

Hence, the angle of elevation is equal to
.
Answer:
A
Step-by-step explanation:
5 is the hypotenuse, 3 is the opposite side, and 4 is the adjacent side. Thus, the cosine of A is adjacent/hypotenuse, hence 4/5.
The area covered by the canal in 30 mins is 562500 sq m
Step-by-step explanation:
Step 1 :
Given,
The canal's width = 6 meter
The canal's Depth is given as 1.5 meter
Speed of the water flowing = 10 kilometer per hour
We need to determine the area which will be irrigated in 30 mins
Step 2 :
In one hour the canal flows 10 kilometer , therefore in 30 minutes it covers 5 kilometer = 5 ×
meter
Hence the volume of the water irrigated per 30 minutes = 6 × 1.5 × 5 ×
= 45 ×
cubic meter
The standing water is 8 centimeter = 8 ×
meter
Hence the area covered in 30 min = Volume ÷ the height of the standing water
= (45 ×
) ÷ 8 ×
meter
= 562500 square meter
Step 3 :
The area covered by the canal in 30 mins is 562500 square meter