Answer:
4 or 4/1 (both the same thing just with plotting point writing 4/1 is easier for me so I know to go up 4 over 1 :) )
Step-by-step explanation:
Parallel lines have the same slope, so both lines will have the same slope. Use line 1’s points to find the slope with the formula
(y1-y2)/(x1-x2)
(5-1)/(-2-(-3)
4/1=4
<h3>
Answer:</h3>
The sides are
6 inches, 8 inches and 10 inches
<h3>
</h3><h3>
Explanation:
</h3>
I'd suggest that the question should read 'The perimeter of a triangle is 24 inches. The longest side is 4 inches longer than the shortest side, and the shortest side is three-fourths the length of the middle side. How do you find the length of each side of the triangle?'
Then the shortest side is
6
and the longest side is
10
<h2>
I hope this helps :)</h2>
To find the difference in two lengths we need to subtract them
but here both length are given in mix fraction form
let us first try to write them in simple fraction form .
the first is : 2 7/8 we write it as : (8* 2 + 7 )/ 8 = 23/8
The second is : 1 1/2 we write it as : ( 2*1 + 1) /2 = 3/2
Let us now try finding difference : 23/8 - 3/2
as both have different number in the bottom we try to make a same number in denominator of both fractions .
2 can become by multiplying it to 4 .
let us multiply 3/2 by 4/4 it makes : ( 12 /8 )
now both fractions can be subtracted . (23/8 ) - ( 12/8 )
( 23 - 12 ) /8 = ( 11/8 )
that is the answer : 11/8 miles.
Answer:
We fail to reject the null hypothesis that the average content of containers of the lubricant is 10 liters, this at the significance level of 0.01
Step-by-step explanation:
Let X be the random variable that represents the content of a container of the lubricant. We have observed n = 10 values, 
= 10.06 and s = 0.2459. We assume that X is normally distributed.
We have the following null and alternative hypothesis
vs 
(two-tailed alternative)
We will use the test statistic
because we have a small sample size. And the observed value is
if 
is true, then T has a t distribution with n-1 = 9 degrees of freedom.
The rejection region for a two-tailed alternative and a significance level of 0.01 is given by RR = {t | t < -3.2498 or t > 3.2498}, where 3.2498 is the value such that there is an area of 0.005 above this number and under the density of the t distribution with 9 df.
Because the observed value 0.7716 does not fall inside RR, we fail to reject the null hypothesis.
X2 - 25 = 0
Add 25 on each side.
x2 = 25
Divide by 2 on each side.
x = 12.5
