Reactant C is the limiting reactant in this scenario.
Explanation:
The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.
Balanced chemical reaction is:
A + 2B + 3C → 2D + E
number of moles
A = 0.50 mole
B = 0.60 moles
C = 0.90 moles
Taking A as the reactant
1 mole of A reacted to form 2 moles of D
0.50 moles of A will produce 
= 
thus 0.50 moles of A will produce 1 mole of D
Taking B as the reactant
2 moles of B reacted to form 2 moles of D
0.60 moles of B reacted to form x moles of D
= 
x = 2 moles of D is produced.
Taking C as the reactant:
3 moles of C reacted to form 2 moles of D
O.9 moles of C reacted to form x moles of D
= 
= 0.60 moles of D is formed.
Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.
The answer is number three because when electrons get excited they move up to the higher energy levels, and they emit light as the come back down to the lower quanta.
Baking soda and dish soap! youre welcome
Answer:
AgI, AgBr, AgCl and Ag₂CrO₄
Explanation:
Ksp (product solubility constant) is defined as the equilibrium constant of the general reaction:
XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)
<em>Where X is cation and Y is anion.</em>
Ksp = [aXⁿ⁺]ᵃ [nYᵃ⁻]ⁿ
The presence of XₐYₙ(s) produce ax moles of aXⁿ⁺ and nx moles of Yᵃ⁻. <em>Where X is the solubility of the compound.</em>
Replacing in Ksp:
Ksp = [ax]ᵃ [nx]ⁿ
Solving for x, Solubility (S) is defined as:
![S = \sqrt[n+a]{\frac{Ksp}{a^{a} n^n} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5Bn%2Ba%5D%7B%5Cfrac%7BKsp%7D%7Ba%5E%7Ba%7D%20n%5En%7D%20%7D)
For AgCl, Ag₂CrO₄, AgBr and AgI solubilities are:
![S = \sqrt[2]{\frac{1.8x10^{-10}}{1} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B2%5D%7B%5Cfrac%7B1.8x10%5E%7B-10%7D%7D%7B1%7D%20%7D)
= 1.34x10⁻⁵M
![S = \sqrt[3]{\frac{1.1x10^{-12}}{4} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B1.1x10%5E%7B-12%7D%7D%7B4%7D%20%7D)
= 6.50x10⁻⁵M
![S = \sqrt[2]{\frac{5.4x10^{-13}}{1} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B2%5D%7B%5Cfrac%7B5.4x10%5E%7B-13%7D%7D%7B1%7D%20%7D)
= 7.35x10⁻⁷M
![S = \sqrt[2]{\frac{8.5^{-17}}{1} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B2%5D%7B%5Cfrac%7B8.5%5E%7B-17%7D%7D%7B1%7D%20%7D)
= 9.22x10⁻⁹M
The lower solubility is the first compound in precipitate, thus, order of precipitation is:
<em>AgI, AgBr, AgCl and Ag₂CrO₄</em>
