Question

For the reaction Ti(s)+2F2(g)→TiF4(s) compute the theoretical yield of the product (in grams) for each of the following initial amounts of reactants. Part A 5.0 g Ti, 5.0 g F2 Express your answer using two significant figures.

Answer 1

Answer:

The answer to your question is 8.2 g of TiF₄

Explanation:

Data

Theoretical yield = ?

mass of Ti = 5 g

mass of F₂ = 5 g

Balanced chemical reaction

                  Ti(s) +  2F₂ (g)   ⇒   TiF₄(g)

Process

1.- Calculate the Molar mass of reactants and products

Ti = 48 g

2F₂ = 2( 19 x 2) = 76 g

TiF₄ = 48 + 76 = 124 g

2.- Calculate the limiting reactant

theoretical proportion Ti/F₂  = 48/76 = 0.63

experimental proportion Ti/F₂ = 5/5 = 1

Conclusion The limiting reactant is F₂ because the experimental proportion was lower than the theoretical proportion.

3.- Calculate the theoretical yield using the mass of F₂

                   76 g of F₂ --------------- 124 g of TiF₄

                     5 g of F₂ ---------------  x

                      x = (5 x 124) / 76

                      x = 8.15 g of TiF₄