Can you figure out the next three digits in the pattern 33633456??

In triangle VWX, VW = 4.5 inches, WX = 5.9 inches, Measure of angle W = 28 degrees, and Measure of angle X = 47 degrees. If Tria

yanalaym [24]

Answer:

b.QR = 5.9 cm

d.Measure of angle R = 47 degrees

Step-by-step explanation:

we know that

If two triangles are congruent, then its corresponding angles and corresponding sides are congruent'

we have

Triangle PQR≅ Triangle VWX

so

corresponding sides

PQ≅VW

QR≅WX

PR≅VX

corresponding angles

∠P≅∠V

∠Q≅∠W

∠R≅∠X

Verify each statement

a.QR = 4.5 cm

we know that

QR≅WX

and

WX=5.9 cm

therefore

The statement is false

b.QR = 5.9 cm

we know that

QR≅WX

and

WX=5.9 cm

therefore

The statement is true

c. Measure of angle R = 28 degrees

we know that

∠R≅∠X

we have

∠X=47°

therefore

The statement is false

d.Measure of angle R = 47 degrees

we know that

∠R≅∠X

we have

∠X=47°

therefore

The statement is true

8 0

3 years ago

Read 2 more answers

If an angle of 96 degrees is rotated 90 degrees clockwise. what the measure?

Natali [406]

Answer:

The measure is 6°.

Step-by-step explanation:

If an angle of 96 degrees is rotated 90 degrees clockwise then the measure of the new angle will be given by

= 96° - 90° = 6°

3 0

3 years ago

Use the graph to answer the question. Which of the following points would be a solution

katrin2010 [14]

Answer:

(1,3)

Step-by-step explanation:

Only point that lies in the blue area.

8 0

3 years ago

Read 2 more answers

Suppose that it is known that the number of items produced in a factory during a week is a random variable with mean 50. If the

iVinArrow [24]

Answer:

The probability would be 0.9586

Step-by-step explanation:

Given,

Mean, $\mu = 50$ ,

Variance, $\sigma^2 = 24$

Standard deviation,

$\sigma = \sqrt{24}=2\sqrt{6}$ ,

If X represents the number of items produced in a factory during a week.

Hence, the probability that this weeks production will be between 40 and 60

$=P(40 < X < 60)$

$=P(\frac{40-\mu}{\sigma} < \frac{X-\mu}{\sigma} < \frac{60-\mu}{\sigma})$

$=P(\frac{40-50}{2\sqrt{6}} < z < \frac{60-50}{2\sqrt{6}})$

$=P(-\frac{10}{2\sqrt{6}} < z < \frac{10}{2\sqrt{6}})$

$=P(-2.041 < z < 2.041)$

$=P(z< 2.041) - P(z< -2.041)$

Using z score table

= 0.9793 - 0.0207

= 0.9586

4 0

3 years ago

The functions f and g are differentiable for all real numbers x. The table below gives values for the functions and their first

sertanlavr [38]

Answer:

13/9

y =-22x+32

Step-by-step explanation:

Given that the functions f and g are differentiable for all real numbers x. The table below gives values for the functions and their first derivatives at selected values of x.

x f(x) f'(x) g(x) g'(x)

1 4 -3 5 2

2 -3 -1 4 6

3 π 8 -1 4

4 -5 unknown 0 3

a) $h(x) = \frac{f(x)}{g(x)} \\h'(x) = \frac{g(x)f'(x)-f(x)g'(x)}{(g(x))^2}$

(using quotient rule)

Substitute 1 for x

$h'(1) = \frac{g(1)f'(1)-f(1)g'(1)}{(g(1))^2}\\=\frac{9-(-4)}{9} \\=\frac{13}{9}$

b) $r(x) = f(x) g(x)\\r'(x) = f(x) g'(x)+g(x)f'(x)$

when $x =2, r(x) = r(2) = f(2) g(2) = -12$

point of contact is (2,-12)

Slope of tangent = $r'(2) = f(2) g'(2)+g(2)f'(2)\\=-18+(-4) \\=-22$

Using point slope form, tangent is

$y+12 = -22(x-2)\\y = -22x +32$

7 0

4 years ago