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BabaBlast [244]

3 years ago

13

I’m taking a test plz anyone help!

1 answer:

Mandarinka [93]3 years ago

7 0

Ok so, basically reflect the shape horizontally across the y - intercept. In the exact same position but reflected across. I’m not sure because I can’t really see the points. Does it give you options? Or do you have to type it?

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How do I figure this out?

Lelechka [254]

Answer:

shoulda woulda coulda been B

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Boyd grows only tomatoes and raspberries in his garden. Last year, he grew 140 pounds of tomatoes and 60 pounds of raspberries.

nadya68 [22]

Answer:

29%.

Step-by-step explanation:

We have been given that Boyd grew 140 pounds of tomatoes and 60 pounds of raspberries. This year, the production, by weight, of tomatoes declined by 20 percent, and the production, be weight, of raspberries declined by 50 percent.

First of all, we will find the weight of tomatoes and raspberries using the given information.

Since the production, by weight, of tomatoes declined by 20 percent, so this year production of tomatoes is 80% of 140 pounds.

$\frac{80}{100}\times 140=0.80\times 140=112$

Since the production, be weight, of raspberries declined by 50 percent, so this year production of raspberries is 50% of 30 pounds.

$\frac{50}{100}\times 60=0.50\times 60=30$

Total production this year: $112+30=142$ pounds.

Now, we will percent decrease formula.

$\text{Percent decrease}=\frac{\text{Initial value-Final value}}{\text{Initial value}}\times 100$

$\text{Percent decrease}=\frac{(140+60)-142}{140+60}\times 100$

$\text{Percent decrease}=\frac{(200)-142}{200}\times 100$

$\text{Percent decrease}=\frac{58}{200}\times 100$

$\text{Percent decrease}=0.29\times 100$

$\text{Percent decrease}=29$

Therefore, the total yield, by weight, of Boyd's garden declined by 29%.

5 0

3 years ago

-2(70-4exponet3)+10 <br> What do i do first

aleksandrvk [35]

HERE IS THE ORDER
Parentheses
Exponents
Multiply
Divide
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Subtract

3 0

3 years ago

Use the quadratic formula to find the solutions to the equation x^2-3x+1=0

Gnom [1K]

Answer:

$x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}$

Step-by-step explanation:

Using:

$x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}$

we will have two solutions.

x^2-3x+1=0

So, a=1 b=-3 c=1

$x_{1}=\frac{+3+\sqrt{-3^{2}-4*1*1} }{2*1}\\\\x_{2}=\frac{+3-\sqrt{-3^{2}-4*1*1} }{2*1}$

We have two solutions:

$x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}$

4 0

3 years ago

The area of a triangle is 12 cm squared. If the base of the triangle is 4 cm what is the height

nlexa [21]

Answer:

6 cm

Step-by-step explanation:

3 0

3 years ago