3 years ago

I’m taking a test plz anyone help!

1 answer:

7 0

Ok so, basically reflect the shape horizontally across the y - intercept. In the exact same position but reflected across. I’m not sure because I can’t really see the points. Does it give you options? Or do you have to type it?

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A cylinder and a cone have the same volume. The cylinder has radius x and height y. The cone has radius 2x. Find the height of t

weqwewe [10]

V(cylinder)=πR²H
Radius of the cylinder R=x, height of the cylinder H=y.
We can write for the cylinder
V(cylinder)=πx²y

V(cone) =(1/3)πr²h
Radius of the cone r=2x.
We can write for the cone
V(cone)= (1/3)π(2x)²h=(1/3)π *4*x²h

V(cylinder) =V(cone)
πx²y=(1/3)π *4*x²h
y=(4/3)*h
h=(3/4)*y

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3 years ago

What is the value of x in the regular polygon? The value of x is?

brilliants [131]

Answer:

Step-by-step explanation:

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3 years ago

What would this be? Thanks for helping!

igor_vitrenko [27]

Answer:

if I remember correctly it would be a triangle.

6 0

2 years ago

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The difference of a number and 6 is the same as 5 times the sum of the number and 2. What is the number?

Sunny_sXe [5.5K]

Answer:.OA. -4

Step-by-step explanation:

4 0

3 years ago

Find the value of x.

konstantin123 [22]

Answer:

x= 37.5°

Step-by-step explanation:

∠CBD

= 180° -75° (adj. ∠s on a str. line)

= 105°

∠BCD= ∠BDC (base ∠s of isos. △BCD)

∠BCD= x

∠BCD +∠BDC +∠CBD= 180° (∠ sum of △BCD)

x +x +105°= 180°

2x= 180° -105°

2x= 75°

x= 37.5°

Alternative working:

∠BDA= (180° -75°) ÷2 (base ∠s of isos. △ABD)

∠BDA= 52.5°

∠BDA +∠BDC= 90°

52.5° +x= 90°

x= 90° -52.5°

x= 37.5°

6 0

3 years ago