Answer:
Question is incomplete.
Assuming the below info to complete the question
You have a collection of n lockboxes and m gold keys. Each key unlocks at most one box. Without a matching key, the only way to open a box is to smash it with a hammer. Your baby brother has locked all your keys inside the boxes! Luckily, you know which keys (if any) are inside each box.
Detailed answer is written in explanation field.
Explanation:
We have to find the reachability using the directed graph G = (V, E)
In this V are boxes are considered to be non empty and it may contain key.
Edges E will have keys .
G will have directed edge b1b2 if in-case box b1 will have key to box b2 and box b1 contains one key in it.
Suppose if a key opens empty box or doesn’t contain useful key means can’t open anything , then it doesn’t belongs to any edge.
Now, If baby brother has chosen box B, then we have to estimate for other boxes reachability from B in Graph G.
If and only if all other boxes have directed path from box B then just by smashing box B we can get the key to box b1 till last box and we can unlock those.
After first search from B we can start marking all other vertex of graph G.
So algorithm will be O ( V +E ) = O (n+m) time.
Answer:
DDos or Distributed Denial Of Service Attack
Explanation:
:)
Answer:
The five eras are general- purpose mainframe and minicomputer computing, personal computers, client/server networks, ...
CAVA’s Academic Integrity Policy refers to Calfornia Virtual Academic’s policy book for students of their schools, which are public charter schools in the state of California.
In the handbook, it is mentioned that students who commit plagiarism will be required to re-submit the assignment during the first offence; will receive a fail grade for the assignment during the second offence; and will be withdrawn from a course or even the school during the third offence.
Thus the answer to the question is (D) all of the above.
In 2009 at least 48,516 people were convicted of DUI and in 2010 at least 43,568. Both of the years together adds up to 92,084.
Hope this helps!
