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Blababa [14]
2 years ago
6

=

Mathematics
1 answer:
kenny6666 [7]2 years ago
6 0

The cost to equip all the stations in the chemistry lab is calculated as: $393.75.

<h3>How to Calculate Total Cost?</h3>

In this scenario, we are given the following:

Total number of stations = 21 stations

Length of rubber tubing each of the stations in the chemistry lab needs = 5 feet

Total length of rubber tubing needed for all stations in the chemistry lab = 21 × 5 = 105 feet

Cost of 1 rubber tubing = $6.25 per yard

Convert 5 feet to yard:

1 yard = 3 feet

x yard = 5 feet

x = (5 × 1)/3

x = 5/3 feet.

So, the cost of 1 rubber tubing = $6.25 per 5/3

Cost of total length of tubbing needed = (105 × 6.25)/5/3 = (105 × 6.25) × 3/5

Cost of total length of tubbing needed = $393.75

Therefore, the cost to equip all the stations in the chemistry lab is calculated as: $393.75.

Learn more about the How to Calculate Total Cost on:

brainly.com/question/2021001

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I need to answer and explain
nignag [31]

Answer:

parallel

Step-by-step explanation:

Solve both equations for y to make it easier to compare them.

2x - 5y = 0 ↔ 5y = 2x, or y = (5/2)x.

y = (5/2)x - 3

Since the slopes are the same, the two lines are parallel.

8 0
3 years ago
Is sin theta=5/6, what are the values of cos theta and tan theta?
mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}

5 0
3 years ago
I would appreciate if someone could help me with this problem and answer it I will give you a brainlist :)
aev [14]
To me from the picture, all sides look the same. so I’m guessing it’s probably 11
8 0
3 years ago
Read 2 more answers
I need help pls !!!!
Phantasy [73]

Answer:

See Below

Step-by-step explanation:

Ok, so in this problem you have some vertical angles. These are angles oppisites from each other. Therefore; d = 52, f = ?, and e = 77. All the angles added together will = 360. Let's add up the angles we know and subtract the whole from 360.

52 + 52 + 77 + 77 = ?

104 + 154 = 258

360 - 258 = 102

Since we know that f and the unlabeled angle are the same, we need to divide this total between the two of them.

102/2 = 51

Therefore;

d = 52

e = 77

f = 51

3 0
3 years ago
A number is equal to twice a smaller number plus 3. Yhe same number is equal to twice the sum of smaller number and 1. How many
allsm [11]

Answer:

There is no solution to the problem

Step-by-step explanation:

In order to find the solutions to the problem you can write the situation in an algebraic form.

You have that a number is equal to twice a smaller number plus 3. This can be written as follow:

x=2y+3      (1)

where x is the number and y is the smaller number

Furthermore, the same number x is equal to twice the sum of the smaller number and 1, which can be written as follow:

x=2(y+1)     (2)

To find the solution you equal the equation (1) with (2), and you solve for y:

2y+3=2y+1

3=1

You obtain an inconsistency, hence, the situation of the problem does not have solution

5 0
3 years ago
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