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3 years ago

What is -3y+5x=12 in slope intercept form

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

8 0

Answer:

y= $\frac{3}{5}$ x-4

Step-by-step explanation:

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Solve x2 + 10x = 24 by completing the square. Which is the solution set of the equation? {–12, 2} {–2, 12}

guajiro [1.7K]

Answer: I could be wrong so don't get your hopes up but I believe the solution set would be {-2,12}

Step-by-step explanation:

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3 years ago

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How is 0.09 smaller than 0.1

denis-greek [22]

Answer:

$0.09 < 0.1$

Step-by-step explanation:

Remember that it doesn't matter how many numbers are after the tenths place of a decimal point what matters is the tenths place itself. If you have a decimal that has dozens of numbers but it's tenth place is a 3 and then you have a decimal with 5 numbers in whole but it's tenths place is 4, the 4 is greater then the 3 simply because it's greater in tenths.

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2 years ago

Multiply: (x – 4)(x + 5)

denpristay [2]

Answer:

D. x2 + x - 20.

Step-by-step explanation:

(x – 4)(x + 5).

= x(x + 5) -4(x + 5).

= x2 + 5x – 4x – 20.

= x2 + x - 20.

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3 years ago

FREE PTS! If there was one thing you could change in the past, what would it be?

m_a_m_a [10]

Answer:

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2 years ago

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30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

5 0

2 years ago