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2 years ago

Please help me with this question I’m rlly confused!!!

Mathematics

1 answer:

aleksandr82 [10.1K]2 years ago

8 0

The measure of centre are mean, median and mode.

The measure of variation are the range, the interquartile range (IQR), variance

<h3>What is measure of centre and variation?</h3>

A measure of central tendency is a summary measure that attempts to describe a whole set of data with a single value that represents the middle or centre of its distribution.

The measure of variation in statistics are ways to describe the distribution or dispersion of your data.

Therefore, the description that depict measure of centre are as follows:

She added all the value and divide the value by 5
She found the middle value after arranging all the values from the least to the greatest.
She found the value that appear most

Therefore, the description that depict measure of variation are as follows:

She found the difference between the least and the greatest values.
She found the difference of the upper quartile and the lower quartile.
She found the mean and then the average deviation of the weight from the mean.

learn more on measure of centre and variation here: brainly.com/question/5495004

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Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Who weighs more relative to other babies of the same gestation period?

Whoever has the higer z-score

33 - week baby.

Babies born after a gestation period of 32-35 weeks have a mean weight of 2700 grams and a standard deviation of 700 grams. A 33-week gestation baby weighs 2950 grams.

We have to find z when $\mu = 2700, \sigma = 700, X = 2950$ . So

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40-week baby

Mean weight of 3000 grams and a standard deviation of 490 grams. 40-week gestation baby weighs 3150 grams.

We have to find Z when $\mu = 3000, \sigma = 490, X = 3150$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3150 - 300}{490}$

$Z = 0.306$

The 33 week gestation period baby has the higher z-score, so he weighs more relative to other babies of the same gestation period.

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