The equation of the given parabola is y2=−20(x+3)
A parabola is a symmetrical open plane curve formed by the intersection of a cone with a plane parallel to its side. The path of a projectile under the influence of gravity ideally follows a curve of this shape.
In general in a parabola, if we have
(y−n)2=4p(x−m),
then the vertex is (m,n)
The axis of symmetry is y=m
The focus is (p+m,n)
The directrix is x=m−p.
Hence, for the given case
p+m=−8
n=0
m−p=2
⇒n=0
m=−3
p=−5
So, the answer will be y2=−20(x+3)
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