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sineoko [7]
2 years ago
13

Hassan and Tamika are helping their friend Cai move. If Hassan can move 4 boxes for every 12 boxes that Tamika moves, then how m

any boxes can Tamika move for every box that Hassan moves?
Mathematics
1 answer:
slavikrds [6]2 years ago
3 0

The computation shows that Tamika can move 3 boxes for every box that Hassan moves.

<h3>How to illustrate the information?</h3>

From the information, it was stated that Hassan can move 4 boxes for every 12 boxes that Tamika moves.

Therefore, the number of boxes that Tamika can move for every box that Hassan moves will be:

= 12/4

= 3

Therefore, Tamika can move 3 boxes for every box that Hassan moves.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

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Goryan [66]
All we have to do for this is multiply 5.4 by 1000, since the ration already has liters as 1.
5.4 × 1000 = 5,400
There are 5,400 milliliters of juice in the jar.
3 0
3 years ago
PLEASE PLEASE HELP &lt;3
anzhelika [568]

Answer:

C

Step-by-step explanation:

∠ AFD = ∠ AFB + ∠ BFC + ∠ CFD

The 3 angles form a straight angle and sum to 180°, that is

4x + 5 + 6x + 3 + 5x + 7 = 180, that is

15x + 15 = 180 ( subtract 15 from both sides )

15x = 165 ( divide both sides by 15 )

x = 11

∠ CFD = 5x + 7 = 5(11) + 7 = 55 + 7 = 62°, thus

∠ AFE = ∠ CFD = 62° ( vertical angles are congruent )

3 0
3 years ago
Can somebody please help me with this problem:Mark has 312 books in his bookcases.He has 11 times as many fiction books as nonfi
egoroff_w [7]
He has 26 fiction books.
8 0
3 years ago
Read 2 more answers
HELP PLSSSS
True [87]

maybe try -5 since the rise/run is 5/1 and the slope is negative

6 0
3 years ago
What the second answer ​
Debora [2.8K]

Answer:

1. y' = 3x² / 4y²

2. y'' = 3x/8y⁵[(4y³ – 3x³)]

Step-by-step explanation:

From the question given above, the following data were obtained:

3x³ – 4y³ = 4

y' =?

y'' =?

1. Determination of y'

To obtain y', we simply defferentiate the expression ones. This can be obtained as follow:

3x³ – 4y³ = 4

Differentiate

9x² – 12y²dy/dx = 0

Rearrange

12y²dy/dx = 9x²

Divide both side by 12y²

dy/dx = 9x² / 12y²

dy/dx = 3x² / 4y²

y' = 3x² / 4y²

2. Determination of y''

To obtain y'', we simply defferentiate above expression i.e y' = 3x² / 4y². This can be obtained as follow:

3x² / 4y²

Let:

u = 3x²

v = 4y²

Find u' and v'

u' = 6x

v' = 8ydy/dx

Applying quotient rule

y'' = [vu' – uv'] / v²

y'' = [4y²(6x) – 3x²(8ydy/dx)] / (4y²)²

y'' = [24xy² – 24x²ydy/dx] / 16y⁴

Recall:

dy/dx = 3x² / 4y²

y'' = [24xy² – 24x²y (3x² / 4y² )] / 16y⁴

y'' = [24xy² – 18x⁴/y] / 16y⁴

y'' = 1/16y⁴[24xy² – 18x⁴/y]

y'' = 1/16y⁴[(24xy³ – 18x⁴)/y]

y'' = 1/16y⁵[(24xy³ – 18x⁴)]

y'' = 6x/16y⁵[(4y³ – 3x³)]

y'' = 3x/8y⁵[(4y³ – 3x³)]

6 0
3 years ago
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