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lara [203]
4 years ago
15

A pyramid with a square base has how many faces?

Mathematics
1 answer:
mylen [45]4 years ago
3 0

Answer:

It has 5 Faces. The 4 Side Faces are Triangles. The Base is a Square. It has 5 Vertices (corner points)


Step-by-step explanation:


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WILL BE MARKED BRAINLIEST PLEASE HELP!!!!!!!!!
salantis [7]

Answer:

x_{3}=2

The first term is \frac{1}{2}

 

5 0
3 years ago
3+5^2??????????????????????????????????????
borishaifa [10]
The answer is 28
bc 3+(5x5) = 3+25 and 3+25 is 28
4 0
3 years ago
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According to the Rational Root Theorem, which number is a potential root of f(x) = 9x8 + 9x6 – 12x + 7?
notsponge [240]

<u>Answer-</u>

\boxed{\boxed{\frac{7}{3}}}

<u>Solution-</u>

Rational Root Theorem-

f(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+.......+a_1x+a_0\ \ \ and\ a_n\neq 0

All the potential rational roots are,

=\pm (\dfrac{\text{factors of}\ a_0}{\text{factors of}\ a_n})

The given polynomial is,

f(x) = 9x^8 + 9x^6-12x + 7

Here,

a_n=9,\ a_0=7\\\\\text{factors of}\ 9=1,3,9\\\\\text{factors of}\ 7=1,7

The potential rational roots are,

=\pm \frac{1}{1},\pm \frac{1}{3}, \pm \frac{1}{9}, \pm \frac{7}{1}, \pm \frac{7}{3}, \pm \frac{7}{9}

=\pm 1,\pm \frac{1}{3}, \pm \frac{1}{9}, \pm 7, \pm \frac{7}{3}, \pm \frac{7}{9}

From, the given options only \frac{7}{3} satisfies.

6 0
3 years ago
Read 2 more answers
NEED ANSWER ASAP- MARK AS BRANLIEST
azamat

Answer:

  x = 1 +√5

Step-by-step explanation:

There are different formulas for the area of a triangle available, depending on the given information.

<h3>Formulas</h3>

When two sides and the angle between them are given, the relevant area formula is ...

  Area = 1/2(ab)sin(C)

When the base and height of a triangle are given, the relevant area formula is ...

  Area = 1/2bh

<h3>Equal Areas</h3>

The problem statement tells us the two triangles shown have equal areas. That means the two formulas will give the same result.

  Area from angle = Area from base/height

  1/2(x·x)sin(30°) = 1/2(x-2)(x+1)

  x² = 2(x² -x -2) . . . . . . . . . . . use sin(30°) = 1/2, multiply by 4

  x² -2x -4 = 0 . . . . . . . . subtract x², eliminate parentheses

  (x -1)² = 5 . . . . . . . . . add 4+1 to complete the square

<h3>Value of x</h3>

  x = 1 ± √5 . . . . . . take the square root, add 1

The value of x must be greater than 2 in order for the triangle side lengths to be positive. (x-2 > 0) This means x = 1-√5 is an extraneous solution.

The value of x is 1 +√5.

5 0
3 years ago
3x + 10 = 1<br><br> I do not know how to solve this pls help me
egoroff_w [7]

Answer:

x=−3

Step-by-step explanation:

Move all terms that don't contain

x to the right side and solve.

hope this helps !

4 0
2 years ago
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