Question

Thomas collects dimes and quarters in his change jar. if he has 4 more dimes than quarters, and the total amount of money in the jar is $26.30, find the number of each type of coin in the jar?

Answer 1

There are 75.29 quarters and 79.29 dimes in the jar.

Given,

In his change jar, Thomas collects dimes and quarters.

So if he has 4 more dimes than quarters, and the total amount of money in the jar is $26.30

Thus,

Let, x be the number of dimes.

And y be the number of quarters.

If Thomas has 4 more dimes than quarters,

y = x + 7

On the other hand, the total amount of money in the jar is $26.30.

0.24x + 0.10y = 26.30

Substitute the value of y in the given equation 2

0.24x + 0.10y = 26.30

0.24x + 0.10 (x+7) = 26.30

0.24x + 0.10x + 0.7 = 26.30

0.34x = 26.30 - 0.7

0.34x = 25.6

x = 25.6 / 0.34

x = 75.29

Substitute the value of x in the given equation 1

y = x + 4

y = 75.29 + 4

y = 79.29

Hence, there are 75.29 quarters and 79.29 dimes in the jar.

To learn more about quarters here:

brainly.com/question/14198492

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