Question

There are 2 buildings, a and b. a had twice as many visitors as b. 2,950 went to a from b. now a has 39,500 more visitors than b. how many visitors altogether?

Answer 1

There are 100800 visitors there altogether in both the buildings.

Let the number of visitors in building b be x.

Visitors in building a will be = 2 x

Now, 2,950 went to a from b.

Visitors in building a = 2 x + 2950

Visitors in building b = x - 2950

ATQ: now a has 39,500 more visitors than b.

We get the equation as:

x - 2950 + 39500 = 2x + 2950

x + 36550 = 2x + 2950

2x - x = 36550 - 2950

x = 33600

2 x = 67200

Total visitors = x + 2x = 33600 + 67200

Total visitors = 100800

Therefore, there are 100800 visitors there altogether in both the buildings.

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