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mars1129 [50]
2 years ago
9

Solve the equation below. Indicate which solutions, if any, are extraneous. √ x+5 = x+3

Mathematics
1 answer:
ahrayia [7]2 years ago
3 0

9514 1404 393

Answer:

  x = -1

Step-by-step explanation:

A graphical solution can avoid extraneous solutions. The attachment shows the one solution is x = -1.

__

Squaring both sides gives ...

  x +5 = (x +3)² = x² +6x +9

Putting this in standard form, we have ...

  x² +5x +4 = 0

  (x +1)(x +4) = 0 . . . . . factor

  x = -1 or -4 . . . . . . . . values of x that make the factors zero

__

Since we require the root to be non-negative, we must have ...

  x +3 ≥ 0

  x ≥ -3

The only solution that satisfies this requirement is x = -1. The solution x = -4 is extraneous. The solution is x = -1.

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77julia77 [94]

Answer:

Option C   f (x) = x^ 2 - 2

Step-by-step explanation:

Note that the relation describing the set of ordered pairs does not change at a costing rate

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Therefore the relationship is not linear.

However, the exchange rate y_n- y_{n-1} increases by a factor of 2 units when n increases 1 unit. This allows us to conclude that the relationship is quadratic

Note that the following ordered pairs belong to the function

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The set of ordered pairs that we have is:

B = {(2, 2), (3, 7), (4, 16), (5, 23)}

Note that there is a similarity between both sets of ordered pairs.

In set B the values of y are always 2 units less than the values in y of the set A.

Then we deduce that since the function that models the set A is y = x ^ 2 then the function that contains the ordered pairs of the B set is:

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The correct option is option C) f (x) = x^ 2 - 2

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