Question

Pls help due in 10 minutes!!!!!!!!!!!!!!1

Answer 1

Answer:

1

Step-by-step explanation:

Given expression:

$27 \cdot \left(\left(3^3\right)^{-1}\right)$

Following the order of operations, carry out the operations inside the parentheses first:

$\implies 27 \cdot \left(\left(3 \cdot 3\cdot 3\right)^{-1}\right)$

$\implies 27 \cdot \left(27^{-1}\right)$

$\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}:$

$\implies 27 \cdot \left(\dfrac{1}{27^1}\right)$

$\implies 27 \cdot \left(\dfrac{1}{27}\right)$

Convert 27 to a fraction:

$\implies \dfrac{27}{1} \cdot \dfrac{1}{27}$

Cross cancel the common factor:

$\implies \dfrac{\diagup\!\!\!\!\!27}{1} \cdot \dfrac{1}{\diagup\!\!\!\!\!27}$

$\implies \dfrac{1}{1}$

$\implies 1$