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2 years ago

Please I need help Will give brainlest answer !!!

Mathematics

1 answer:

Alecsey [184]2 years ago

5 0

Answer:

Step-by-step explanation:

5 integers with an average of 44

⇒ sum of the integers = 5 x 44 = 220

The median is the middle number when the numbers are put in order of smallest to largest. So the integers are: x x 50 x x

The modal integer is the one that occurs most frequently, so if the mode is 52, then at least 2 of the integer are 52. Since the median is 50, the integers are: x x 50 52 52

Therefore, the remaining two integers are less than 50.

The range is the difference between the largest integer and the smallest integer. As we know that the largest integer is 52 and the range is 27, then the smallest integer is 52 - 27 = 25

25 x 50 52 52

To find the last unknown integer :

⇒ sum of the integers = 25 + 50 + 52 + 52 + x = 220

⇒ x = 41

Therefore, the integers are:

25, 41, 50, 52, 52

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3 years ago

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insens350 [35]

Answer:

The correct answer is OB.

Step-by-step explanation:

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3 years ago

Electricity usage data consists of 45 months has a mean number of units consumed is 390.47 per month with a standard deviation o

neonofarm [45]

Answer:

The 95% confidence interval for the average monthly electricity consumed units is between 47.07 and 733.87

Step-by-step explanation:

We have the standard deviation for the sample. So we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 45 - 1 = 44

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.0141

The margin of error is:

M = T*s = 2.0141*170.5 = 343.4

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 390.47 - 343.40 = 47.07 units per month

The upper end of the interval is the sample mean added to M. So it is 390.47 + 343.40 = 733.87 units per month

The 95% confidence interval for the average monthly electricity consumed units is between 47.07 and 733.87

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2 years ago