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sineoko [7]
3 years ago
11

How to turn 3x = -2y into standard form

Mathematics
1 answer:
zimovet [89]3 years ago
8 0
3x = -2y
or 3x + 2y = 0

it is the standard form.
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Please help I so dumb
kakasveta [241]

its the first one because you would have 3 left over.

6 0
4 years ago
Input the equation of the given line in standard form the line with m=-1/2 and the point (-2,-3)
rosijanka [135]

Answer:

The equation would be x + 2y = -8

Step-by-step explanation:

To find the standard form of this line, start by using point-slope form with the given information. Then solve for the constant.

y - y1 = m(x - x1)

y + 3 = -1/2(x + 2)

y + 3 = -1/2x - 1

1/2x + y + 3 = -1

1/2x + y = -4

x + 2y = -8

8 0
3 years ago
I need help haven’t done math since quarantine and I get an assignment with these it’s not -t exponent 5
MA_775_DIABLO [31]

Answer:

-t^5

Step-by-step explanation:

Since you are multiplying the same thing by itself, it'll have an exponential value, so count the t's and that is your exponent. Don't forget the "-" sign.

7 0
4 years ago
A color printer prints 31 pages in 12 minutes. how many minutes does it take per page?
padilas [110]
12/31 = 0.38 minutes per page 

6 0
3 years ago
Read 2 more answers
Find S18 for geometric series given a5=-6 and a2= -48
Ganezh [65]

an = a1r^(n-1)

a5 = a1 r^(5-1)

-6 =a1 r^4


a2 = a1 r^(2-1)

-48 = a1 r


divide

-6 =a1 r^4

----------------    yields   1/8 = r^3      take the cube root  or each side

-48 = a1 r                     1/2 = r


an = a1r^(n-1)

an = a1 (1/2)^ (n-1)

-48 = a1 (1/2) ^1

divide by 1/2

-96 = a1


an = -96 (1/2)^ (n-1)


the sum

Sn = a1[(r^n - 1/(r - 1)]

S18 = -96 [( (1/2) ^17 -1/ (1/2 -1)]

       =-96 [ (1/2) ^ 17 -1 /-1/2]

      = 192 * [-131071/131072]

 approximately -192

     

       

     

3 0
4 years ago
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