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1 year ago

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Place value of 209,.45

1 answer:

sammy [17]1 year ago

7 0

The place value of decimal number given as 209.45 is two decimal places

<h3>How to determine the place value?</h3>

The decimal number is given as:

Number = 209.45

The place value implies that the number of significant digits after the decimal point

In the given number 209.45, there are 2 significant digits after the decimal point i.e. 4 and 5

Hence, the place value of decimal number given as 209.45 is two decimal places

Read more about place value at

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Since YouTube first became available to the public in mid-2005, the rate at which video has been uploaded to the site can be app

Sergeeva-Olga [200]

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2 years ago

What is the value of x ?20(20-x)=300

tatuchka [14]

X=5 because 20*15=300

3 0

2 years ago

Read 2 more answers

During a field trip, 60 students are put into equal-sized groups. Describe two ways to interpret 60 ÷ 5 in this problem *

sergeinik [125]

Answer:

$x=12 groups$

This will give 5 Students each in 12 different equally sized groups

$x'=5groups$

This also shows that students can grouped in equal groups of 12 in 5 places

Step-by-step explanation:

From the question we are told that

60 children in equal sized groups

Generally interpreting $60\div 5$ can be mathematically represented as

a)

$x=\frac{60}{5}$

$x=12 groups$

This will give 5 Students each in 12 different equally sized groups

b)

$x'=\frac{60}{12}$

$x'=5groups$

This also shows that students can grouped in equal groups of 12 in 5 places

6 0

2 years ago

Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

3 0

3 years ago

The sum of two consecutive multiples of 9 is 63 .Find these multiples

san4es73 [151]

Step-by-step explanation:

divide 63 from 9

=the answer is 7

7 0

2 years ago