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matrenka [14]
3 years ago
7

Find the measure of the are or angle indicated. Assume that lines which appear tanget are tangents​

Mathematics
1 answer:
tamaranim1 [39]3 years ago
4 0

Given:

In a circle, two chords AK and LJ intersect each other inside the circle at M.

Measure of arc AJ = 65 degrees.

Measure of arc KL = 85 degrees.

To find:

The measure of angle KML.

Solution:

Intersecting chords theorem: According to this theorem, if two chords intersect each other inside the circle then the measure of angle on the intersection is half of the sum of intercepted arcs.

Using Intersecting chords theorem, we get

m\angle KML =\dfrac{1}{2}(arcKL+arcAJ)

m\angle KML =\dfrac{1}{2}(85^\circ +65^\circ )

m\angle KML =\dfrac{1}{2}(150^\circ )

m\angle KML =75^\circ

Therefore, the measure of angle KML is 75 degrees.

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Given the following rectangle and circle, at what approximate value of x are the two areas equal? Show work and explain all step
suter [353]

Answer:

x ≈ 1.28

Step-by-step explanation:

I just took the exam:

Area of rectangle =(3x-1)(x+6), Area of circle = PI(x+1)^2. If you graph these and find where they intersect, you will get x ≈ 1.28.

I hope this helped! :)

7 0
3 years ago
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
aliya0001 [1]

Answer:

A=1500-1450e^{-\dfrac{t}{250}}

Step-by-step explanation:

The large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved.

Volume = 500 gallons

Initial Amount of Salt, A(0)=50 pounds

Brine solution with concentration of 2 lb/gal is pumped into the tank at a rate of 3 gal/min

R_{in} =(concentration of salt in inflow)(input rate of brine)

=(2\frac{lbs}{gal})( 3\frac{gal}{min})\\R_{in}=6\frac{lbs}{min}

When the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

Concentration c(t) of the salt in the tank at time t

Concentration, C(t)=\dfrac{Amount}{Volume}=\dfrac{A(t)}{500}

R_{out}=(concentration of salt in outflow)(output rate of brine)

=(\frac{A(t)}{500})( 2\frac{gal}{min})\\R_{out}=\dfrac{A}{250}

Now, the rate of change of the amount of salt in the tank

\dfrac{dA}{dt}=R_{in}-R_{out}

\dfrac{dA}{dt}=6-\dfrac{A}{250}

We solve the resulting differential equation by separation of variables.  

\dfrac{dA}{dt}+\dfrac{A}{250}=6\\$The integrating factor: e^{\int \frac{1}{250}dt} =e^{\frac{t}{250}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{250}}+\dfrac{A}{250}e^{\frac{t}{250}}=6e^{\frac{t}{250}}\\(Ae^{\frac{t}{250}})'=6e^{\frac{t}{250}}

Taking the integral of both sides

\int(Ae^{\frac{t}{250}})'=\int 6e^{\frac{t}{250}} dt\\Ae^{\frac{t}{250}}=6*250e^{\frac{t}{250}}+C, $(C a constant of integration)\\Ae^{\frac{t}{250}}=1500e^{\frac{t}{250}}+C\\$Divide all through by e^{\frac{t}{250}}\\A(t)=1500+Ce^{-\frac{t}{250}}

Recall that when t=0, A(t)=50 (our initial condition)

50=1500+Ce^{-\frac{0}{250}}50=1500+Ce^{0}\\C=-1450\\$Therefore the amount of salt in the tank at any time t is:\\A=1500-1450e^{-\dfrac{t}{250}}

4 0
3 years ago
Find the circumference of the circle (use 3.14 for pi). Round to the nearest tenth.
stich3 [128]

Answer:

37.7

Step-by-step explanation:

The formula is C = 2 • 3.14 • r , you multiply the radius by pi/3.14, then you multiply that by product by 2.

5 0
3 years ago
Determine which graph represents a reflection across the x-axis of f(x) = 3(1.5)x.
vivado [14]

The reflection is written as:

g(x) = -3*(1.5)^x

And the graph can be seen below.

<h3>How to get the graph of the reflection?</h3>

Here we have the function:

f(x) = 3*(1.5)^x

A reflection across the x-axis is given by:

g(x) = -f(x).

Then, replacing the function f(x) by the actual equation:

g(x) = -3*(1.5)^x

The graph of the function g(x) can be seen below:

If you want to learn more about reflections:

brainly.com/question/4289712

#SPJ1

5 0
2 years ago
Help me please I need this answer ASAP
Ket [755]

Answer:

ok

Step-by-step explanation:

5 0
3 years ago
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