We conclude that the vertex of the given quadratic equation is (5, -9).
<h3>
How to find the vertex of the quadratic function?</h3>
Remember that for a general quadratic function:
f(x) = a*x^2 + b*x + c
The x-value of the vertex is:
x = -b/2a
In this case, our quadratic function is:
f(x) = (x - 8)*(x - 2)
Expanding that we get:
f(x) = x^2 - 8x - 2x + 16 = x^2 - 10x + 16
Then the x-value of the vertex is:
x = -(-10)/2*1 = 10/2 = 5
And the y-value of the vertex is what we get when we evaluate f(x) in x = 5, we will get:
f(5) = (5 - 8)*(5 - 2) = -3*3 = -9
Then we conclude that the vertex of the given quadratic equation is (5, -9).
If you want to learn more about quadratic equations:
brainly.com/question/1214333
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