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4 years ago

How multiplied whole number with fraction

2 answers:

Volgvan4 years ago

7 0

I think it helps to turn the whole number into a fraction, just by adding a denominator of 1. Then, you can easily multiply across with both fractions, and simplify the answer once done. Hope this helps!

Fofino [41]4 years ago

3 0

Search it up and you shall find an answer believe me it is there

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What is 5.8 × 106 mg/s in grams per minute?

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4 years ago

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4 years ago

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Complete the equation for the linear function whose graph contains the point (7, 8) and has a slope of −1.2.

svetoff [14.1K]

Your answer is to the question 16,4
<span>Form of the equation: y = mx + b
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You are given that y = 8 when x = 7.
And you are given that m = -1.2
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Substitute for those letters and solve for "b"::
8 = -1.2*7 + b
8 = -8.4 + b
b = 8 + 8.4 = 16.4</span>

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4 years ago

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4 years ago

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Find the Taylor series for f(x)=sin(x) centered at c=π/2.sin(x)=∑ n=0 [infinity]On what interval is the expansion valid? Give yo

agasfer [191]

Answer:

sinx =1-\frac{1}{2} (x-\frac{\pi}{2} )^2+\frac{1}{24} (x-\frac{\pi}{2} )^4-\frac{1}{720} (x-\frac{\pi}{2} )^6+\frac{1}{40320} (x-\frac{\pi}{2} )^8+...

Step-by-step explanation:

given that f(x) = sin x

we have to find the Taylor series for that

$f(x) = sin x : f( = 1\\f'(x) = cos x :(f'\frac{\pi}{2})=0\\f"(x) = -sinx :f" (\frac{\pi}{2}) =-1\\f^4 (x) = -cosx : f^4 (\frac{\pi}{2}) =0$

and so on.

i.e. 2nd, 4th, 6th terms would be 0

and also 1st, 5th, 9th terms would be positive for f value and 3rd, 9th,... would be negative

Using the above we can write Taylor series as

$f(x) = f(a)+\frac{f'(a)}{1!} (x-\frac{\pi}{2}) +...+f^n(a) /n! (x- \frac{\pi}{2})^n+...$

$sinx =1-\frac{1}{2} (x-\frac{\pi}{2} )^2+\frac{1}{24} (x-\frac{\pi}{2} )^4-\frac{1}{720} (x-\frac{\pi}{2} )^6+\frac{1}{40320} (x-\frac{\pi}{2} )^8+...$

This is valid for all real values of x.

x ∈ $(-\infty, infty)$

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3 years ago