Answer:
If one ball is selected at random, the odds for it being stripped are 7 out of 15, or 7/15.
Step-by-step explanation:
We know that there are 15 billiard balls.
We also know that balls numbered 1 through 8 are solid-colored, so we have 8 solid-colored balls.
And the other 7 balls are striped.
Now we want to find the probability for a randomly selected ball to be a striped ball.
Because all the balls have the same probability of being randomly selected, the probability of randomly selecting a striped ball is equal to the quotient between the number of striped balls (7) and the total number of balls (15).
Then we have:
P = 7/15 = 0.467
That quotient is also what is called the "odds"
So if one ball is selected at random, the odds for it being stripped are 7 out of 15, or 7/15.
Given:
The expression is
![\sqrt{\sqrt[3]{6}}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Csqrt%5B3%5D%7B6%7D%7D)
To find:
The simplified form of the given expression.
Solution:
We have,
Using the properties of radical and exponent, we get
![=(\sqrt[3]{6})^{\frac{1}{2}}](https://tex.z-dn.net/?f=%3D%28%5Csqrt%5B3%5D%7B6%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
![[\because \sqrt{x}=x^{\frac{1}{2}}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5D)
![[\because \sqrt[n]{x}=x^{\frac{1}{n}}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5D)
![[\because (a^m)^n=a^{mn}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a%5Em%29%5En%3Da%5E%7Bmn%7D%5D)
Therefore, the correct option is A.
Answer:
Answer is 5 inches on edg
Step-by-step explanation:
Answer:
21
Step-by-step explanation:
Midpoint means the middle, so all you have to do is divide 42 by 2 :)
Answer:
3
0st + 42t
Step-by-step explanation:
that's the answer, so i guess you can explain or are you good?
