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rjkz [21]
2 years ago
12

Math question about statistics ​

Mathematics
1 answer:
ASHA 777 [7]2 years ago
5 0

Answer:

Mean = 29300

median = 23500

Modal = 23000

Step-by-step explanation:

Mean = Add them all and divide by 10

= 29300

median = average of (rank of 5th and 6th)

= (23000 + 24000) /2

= 23500

Modal = appear the most

= 23000

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Please help me AND ALSO PLEASE EXPLAIN HOW YOU WORKED IT OUT thank you.
lesya692 [45]
128, -512, 2048
Multiply by -4 to get each new term
4 0
3 years ago
Use the difference of squares identity to write this polynomial expression in factored form: 9x2 − 49.
qwelly [4]
9x^2-49
It equals:
<span>(<span><span>3x</span>+7</span>)</span><span>(<span><span>3x</span>−7</span><span>)
Hope this helps!
</span></span>
7 0
4 years ago
Read 2 more answers
Find the missing angle measures in the given rhombus.
jeyben [28]

Answer:

(1) = 38\°

(2) = 90\°

(3) = 90\°

(4) = 38\°

Step-by-step explanation:

The diagonals of a rhombus are perpendicular to each other, so angles (2) and (3) are equal 90°.

To find angle (1), we can use the sum of internal angles in the left triangle with angles 52°, (1), and (2):

52 + (1) + (2) = 180

(1) = 180 - 52 - 90

(1) = 38\°

The diagonals of a rhombus bisects the angles, to the angle next to the angle of 52° is also 52°, then, in the upper triangle, we have:

52 + (4) + 90 = 180

(4) = 38\°

3 0
3 years ago
Which angles are corresponding angles?
konstantin123 [22]

Answer:

A. 7 and 3

&

B. 1 and 5

Step-by-step explanation:

Corresponding angles are a pair of angles each of which is on the same side of one of two lines cut by a transversal and on the same side of the transversal.

The answers are:

•8 and 4

•5 and 1

•7 and 3

•6 and 2

I hope this helps! I'm sorry if it's wrong.

3 0
3 years ago
To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

3 0
3 years ago
Read 2 more answers
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