We have to find the potential solutions to
from least to greatest.
Using the properties of ln function.

Therefore, we get


taking antilog on both the sides, we get

So, 
Therefore, the potential solutions to 2 ln x = 4 ln 2 from least to greatest is -4 and 4.
95% confidence interval would be (58.96, 69.04).
Step-by-step explanation:
Since we have given that
Number of dogs' weight = 20
Mean = 64 ounces
Standard deviation = 11.5 ounces
We need to find the 95% confidence interval.
So, z = 1.96
so, interval would be

Hence, 95% confidence interval would be (58.96, 69.04).
You need to make a series of equations from what you are given first. I am going to use the first letter of each of the names to represent the length of that persons wire.
1/2s=2/5d
3c=s
s+d+c=6 ft
Okay. Now you can combine the first two equations knowing what s equals:
1/2(3c)=2/5d
d=15c/4
Now you have d=15c/4 and s=3c, so you can replace d and s in the third equation.
3c+15c/4+c=6
Then solve for c and plug it into the equation 3c=s to find the length of sarah's wire.
I got 523.6in^3 hope this helps