The unit vector with the same direction of the vector <u>v</u> = - 6 i + 2 j - k is <u>u</u> = - (6√41 / 41) i + (2√41 / 41) j - (√41 / 41) k.
<h3>How to determine the unit vector</h3>
Vectors are characterized both by magnitude and direction, unit vectors are vectors with a magnitude of 1. Then, the unit vector can be found by the following formula:
<u>u</u> = <u>v</u> / ||<u>v</u>|| (1)
Where:
- ||<u>v</u>|| - Norm of the vector
- <u>v</u> - Vector
The norm of the vector can be determined by Pythagorean theorem. Then, we find the unit vector:
||<u>v</u>|| = √[(- 6)² + 2² + (- 1)²]
||<u>v</u>|| = √41
<u>u</u> = (- 6 i + 2 j - k) / √41
<u>u</u> = - (6 / √41) i + (2 / √41) j - (1 / √41) k
<u>u</u> = - (6√41 / 41) i + (2√41 / 41) j - (√41 / 41) k
The unit vector with the same direction of the vector <u>v</u> = - 6 i + 2 j - k is <u>u</u> = - (6√41 / 41) i + (2√41 / 41) j - (√41 / 41) k.
To learn more on unit vectors: brainly.com/question/28028700
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