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Alexeev081 [22]
3 years ago
9

The length of a screw produced by a machine is normally distributed with a mean of 0.75 inches and a standard deviation of 0.01

inches. what percent of screws are between 0.72 and 0.78 inches? (1 point 68% 75% 99.7% 100%
Mathematics
2 answers:
Soloha48 [4]3 years ago
7 0

Answer: There is 99.7% of screws are between 0.72 and 0.78 inches.

Step-by-step explanation:

Since we have given that

Mean = 0.75 inches

Standard deviation = 0.01 inches

Since the length of a screw produced by a machine is normally distributed.

So, We need to find the percent of screws are between 0.72 and 0.78 inches.

Since we have that

P(0.72

And we know that

z=\frac{X-\mu}{\sigma}

So, it becomes,

P(\frac{0.72-0.75}{0.01}

Hence, there is 99.7% of screws are between 0.72 and 0.78 inches.

White raven [17]3 years ago
6 0
99.7%
You can use normalCdf(.72,.78,.75,.01) to find the answer or if you standardize your numbers (z scores) normalCdf(-3,3,0,1).
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In ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45. What is the value of the cosine of ∠X to the nearest hundredth?
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The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

Step-by-step explanation:

The given is,

                   In ΔWXY, ∠Y=90°

                        XW = 53

                         YX = 28

                        WY = 45

Step:1

             Ref the attachment,

             Given triangle XWY is right angled triangle.

             Trigonometric ratio's,

                              Cos ∅  = \frac{Adj}{Hyp}    

             For the given attachment, the trigonometric ratio becomes,

                              Cos ∅  = \frac{XY}{XW}.....................................(1)

             Let, ∠X = ∅

             Where, XY = 28

                         XW =  53

             Equation (1) becomes,

                                 Cos ∅  = \frac{28}{53}

                                 Cos ∅ = 0.5283

                                        ∅ = cos^{-1} (0.5283)

                                        ∅ = 58.109°

Result:

          The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

             

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3 years ago
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