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lara [203]
1 year ago
15

What does a 360 degrees rotation look like?

Mathematics
1 answer:
Mademuasel [1]1 year ago
7 0

Answer:

A full rotation of an object

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Use the divergence theorem to calculate the surface integral s f · ds; that is, calculate the flux of f across s. f(x, y, z) = x
valkas [14]
\mathbf f(x,y,z)=x^4\,\mathbf i-x^3z^2\,\mathbf j+4xy^2z\,\mathbf k
\mathrm{div}(\mathbf f)=\dfrac{\partial(x^4)}{\partial x}+\dfrac{\partial(-x^3z^2)}{\partial y}+\dfrac{\partial(4xy^2z)}{\partial z}=4x^3+0+4xy^2=4x(x^2+y^2)


Let \mathcal D be the region whose boundary is \mathcal S. Then by the divergence theorem,

\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV

Convert to cylindrical coordinates, setting

x=r\cos\theta
y=r\sin\theta

and keeping z as is. Then the volume element becomes


\mathrm dV=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz

and the integral is

\displaystyle\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=0}^{z=r\cos\theta+7}4r\cos\theta\cdot r^2\cdot r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle4\iiint_{\mathcal D}r^4\cos\theta\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\dfrac{2\pi}3
4 0
3 years ago
Choose what the expressions below best represent within the context of the word problem. The tens digit of a number is twice the
Usimov [2.4K]
<span>2x + x = 12
=> x =12/3 =4
so, original number is 84.

</span>
6 0
3 years ago
In a video game, Agnes scored 20% fewer than Amy. Amy scored 860
vovangra [49]

Answer:

\huge\boxed{\sf Agnes\ Score = 688\ points}

Step-by-step explanation:

\sf = 20 \% \ of \ 860 \\\\= \frac{20}{100} * 860\\\\= 2 * 86\\\\= 172 \ points

Since, Agnes scored 20 % fever than Amy.

So,

Agnes Score = Amy's Points - 20 % of Amy's Points

Agnes Score = 860 - 172

Agnes Score = 688 points

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>
8 0
3 years ago
What is 35-14+27 i really need help pls anser fast
zhuklara [117]

Answer:

<em>B is the correct answer</em>, The first choice (which you chose) is the incorrect answer.

Step-by-step explanation:

6 0
2 years ago
Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>​
sladkih [1.3K]

Answer:

\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2

\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta

17)  Given:

  • \theta = 240°
  • r = 16 ft

\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2

19)  Given:

  • \theta=\dfrac{3 \pi}{2}
  • r = 14 cm

\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2

21)  Given:

  • \theta=\dfrac{ \pi}{2}
  • r = 10 mi

\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2

23)  Given:

  • \theta = 60°
  • r = 7 km

\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2

3 0
2 years ago
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