9. Find the Highest Common Factor of

Mathematics

2 answers:

labwork [276]3 years ago

6 0

Answer:

90 and 1000

Step-by-step explanation:

e 90 and 1000

netineya [11]3 years ago

3 0

C. 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60

1,000: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

Now we find the common numbers. One doesn’t count as when multiplied later on, it will not change anything.

60: 2, 4, 5, 10, 20

1,000: 2, 4, 5, 10, 20

The highest common factor is 20 because it’s, well, the highest number.

D. Do the same thing for D.

24: 1, 2, 3, 4, 6, 8, 12, 24

880: 1, 2, 4, 5, 8, 10, 11, 16, 20, 22, 40, 44, 55, 80, 88, 110, 176, 220, 440, 880

20 and 880: 2, 4, 8

8 is the Highest Common Factor.

E. Do the same thing with E.

90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

1,000: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

90 and 1000: 2, 5, 10

10 is the Highest Common Factor.

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1) Last Tuesday, Regal Cinemas sold a total of 85 movie tickets. Ticket sales totaled

irakobra [83]

In this question, some of the data is missing so its a complete question and the solution can be defined as follows:

$\bold{\text{m = matinee tickets}} \\\\\bold{\text{s = student tickets}}\\\\\bold{\text{r = regular tickets}}$

By given question, calculating equations are:

$\to \bold{m + s + r = 8500}............................................(a)\\\\\to \bold{5m + 6s + 8.50r = 64600}............................(b)\\\\\to \bold{s = 2m}...................(c)$

Putting the equation (c) value in the equation (a) to calculate value:

$m + 2m + r = 8500\\\\3m + r = 8500\\\\r = 8500 - 3m........................................(d)$

Putting equation (c) and (d) value into equation (b):

$5m + 6(2m) + 8.50(8500 - 3m) = 64600\\\\5m + 12m + 72250 - 25.50m = 64600\\\\-8.50m = 64600 - 72250 \\\\-8.50m = -7650\\\\m = \frac{-7650}{-8.50}\\\\m = \frac{7650}{8.50}\\\\m = 900$