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tekilochka [14]
1 year ago
10

F a = 3, b = 4, what is c if its a right triangle

Mathematics
1 answer:
ANEK [815]1 year ago
6 0

The value of c in the given triangle described by the coordinates is; 5.

<h3>What is the value of c if the triangle is a right triangle?</h3>

Since the side, c is one of the sides of the right triangle in discuss, it follows therefore that from Pythagoras theorem;

hypothenuse² = opposite² + adjacent²

where, c = hypothenuse,

a= opposite/perpendicular,

b = adjacent/base.

C² = 3² + 4²

C² = 9 + 16

C = √25

C = 5.

Ultimately, the value of the hypothenuse, c is; 5.

Read more on Pythagoras theorem;

brainly.com/question/21970437

#SPJ1

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Please help me i need an answer
Kobotan [32]

Answer:

  -15

Step-by-step explanation:

If 18 more is -27, then 3 times the number is 18 less than -27, or -45.

If 3 times the number is -45, the number is -15.

7 0
4 years ago
Little Tikes is currently trying to plan a new sandbox for children. One sandbox they already have is a square and they are adju
lbvjy [14]

Answer:

a. L² = 3L(L - 10)

b. The equation could be used to determine the length of a side of the original sandbox since, the areas of both sandboxes are the same.

c. 225 m²

Step-by-step explanation:

a. Let L represent the length of side of the original square sandbox. Since one side of the new rectangular sandbox is increased by 3, so we have one side as 3L and the other side reduced by 10 meters, we have the other side as L - 10.

The area of the original square sandbox = L²

The area of the new rectangular sandbox = 3L(L - 10).

Since both areas are the same, we equate them.

So, L² = 3L(L - 10)

b. L² = 3L(L - 10)

The above equation could be used to determine the length of a side of the original sandbox since, the areas of both sandboxes are the same.

c. We find the area of the new rectangular garden by first solving the equation to find the length of the original sandbox.

So, L² = 3L(L - 10)

Expanding the brackets

L² = 3L² - 30L

Collecting like terms

3L² - L² = 30L

2L² = 30L

2L² - 30L = 0

2L(L - 15) = 0

2L = 0 or L - 15 = 0

L = 0 or L = 15

Since L ≠ 0 we choose L = 15 meters

So the area of the rectangular sandbox = 3L(L - 10) = 3(15)(15 -10) = 45 × 5 = 225 m²

7 0
4 years ago
What is the solution set of the quadratic inequality 6x^2+1 greater than or equal to 0?
Ratling [72]

Answer:

C

Step-by-step explanation:

6x^2 + 1 <= 0

6x^2 <= -1

x^2 <= -1/6

Since we cannot take the square root of a negative number, there is no solution.

7 0
3 years ago
Nolan rides his bike 63 miles in 270 minutes. What is his average speed in miles per hour?
Karolina [17]
270 minutes = 4,5 hours = 4 hours and 30 minutes
60 minutes = 1 hour

63 miles per 270 minutes
x miles per 1 hour = 60 minutes

\dfrac{63[miles]}{x[miles]} = \dfrac{270[minutes]}{60[minutes]}

63 \cdot 60 = 270x
3780 = 270x\quad |:270
x=14[miles]

His average speed is 14 miles per hour. 

<em>:)</em>
5 0
3 years ago
Which graph represents the solution to the system of equations?<br> y = 22 +5<br> y = ;* - 2
Alja [10]
I hope this helps. Good luck!

7 0
3 years ago
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