Question

Finding the average rate of change of g(z) =4x^2_5 between the points( -2,11) and (2,11

Answer 1

Answer:

The average rate of change of g(z) =4x^2_5 between the points( -2,11) and (2,11) is 0.

Step-by-step explanation:

Given a function y, the average rate of change S of $y=g(z)$ in an interval  $(z_{s}, z_{f})$ will be given by the following equation:

$S = \frac{g(z_{f}) - g(z_{s})}{z_{f} - z_{s}}$

In this problem, we have that:

$g(z) = 4z^{2} - 5$

Between the points( -2,11) and (2,11).

So $z_{f} = 2, z_{s} = -2$

$g(z_{f}) = g(2) = 4*(2)^{2} - 5 = 11$

$g(z_{s}) = g(-2) = 4*(-2)^{2} - 5 = 11$

So

$S = \frac{g(z_{f}) - g(z_{s})}{z_{f} - z_{s}} = \frac{11 - 11}{2 - (-2)} = \frac{0}{4} = 0$

The average rate of change of g(z) =4x^2_5 between the points( -2,11) and (2,11) is 0.