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Bas_tet [7]
1 year ago
6

Which type of software is offered in trial form or for a limited period of time?

Computers and Technology
1 answer:
kkurt [141]1 year ago
3 0

The type of software which is offered in trial form or for a limited period of time is called shareware.

Software which are offered for free in trial form or for a limited time period are called shareware. They operate on the principle that once the user understands what the software can offer they will pay to use it later.

Most shareware software has built in countdowns which start as soon as you start the trial and at the end of which access is automatically revoked. They require the user to form a simple account. These versions generally provide a very basic selection of functions and are used to rake in more paying users.

Types of shareware include:

  1. Adware: It stands for advertising-supported software where the advertisements generate revenues.
  2. Demoware: This is a trial version of the original software including all features.
  3. Crippleware: This software is free but provides limited features till it is purchased.
  4. Trialware

This provides the user with full feature access for a time limit and then requires purchase.

You can learn more about shareware software at

brainly.com/question/4593389

#SPJ4

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in java how do i Write a program that reads a set of integers, and then prints the sum of the even and odd integers.
hammer [34]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to take input from user

public class Main{

public static void main(String[] args) { //start of main function

Scanner input = new Scanner(System.in); // creates Scanner class object  

       int num, integer, odd = 0, even = 0; //declare variables

       System.out.print("Enter the number of integers: "); //prompts user to enter number of integers

       num = input.nextInt(); //reads value of num from user

       System.out.print("Enter the integers:\n"); //prompts user to enter the integers

       for (int i = 0; i < num; i++) { //iterates through each input integer

           integer = input.nextInt(); // reads each integer value

               if (integer % 2 == 0) //if integer value is completely divisible by 2

                   even += integer; //adds even integers

               else //if integer value is not completely divisible by 2

                   odd += integer;  } //adds odd integers

           System.out.print("Sum of Even Numbers: " + even); //prints the sum of even integers

           System.out.print("\nSum of Odd Numbers: " + odd);//prints the sum of odd integers

           }}

Explanation:

The program is explained in the comments mentioned with each line of the code. I will explain the logic of the program with the help of an example.

Suppose user wants to input 5 integers. So,

num = 5

Suppose the input integers are:

1, 2 , 3, 4, 5

for (int i = 0; i < num; i++)  is a for loop that has a variable i initialized to 0. The condition i<num is true because i=0 and num=5 so 0<5. Hence the statements inside body of loop execute.

At first iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 1

if (integer % 2 == 0) checks if integer is completely divisible by 2. The modulo operator is used which returns the remainder of the division and if this remainder is equal to 0 then it means that the integer is completely divisible by 2 and if the integer is completely divisible by 2 then this means the integer is even. 1%2 returns 1 so this means this condition evaluates to false and the integer is not even. So the else part executes:

odd += integer;   this becomes:

odd = odd + integer

odd = 1

Now the value of i is incremented to 1 so i=1

At second iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 2

if (integer % 2 == 0) checks if integer is completely divisible by 2. 2%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even += integer;   this becomes:

even= even+ integer

even = 2

Now the value of i is incremented to 1 so i=2

At third iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 3

if (integer % 2 == 0) checks if integer is completely divisible by 2. 3%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd += integer;   this becomes:

odd= odd + integer

odd= 1 + 3

odd = 4

Now the value of i is incremented to 1 so i=3

At fourth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 4

if (integer % 2 == 0) checks if integer is completely divisible by 2. 4%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even+= integer;   this becomes:

even = even + integer

even = 2 + 4

even = 6

Now the value of i is incremented to 1 so i=4

At fifth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 5

if (integer % 2 == 0) checks if integer is completely divisible by 2. 5%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd+= integer;   this becomes:

odd= odd+ integer

odd= 4 + 5

odd = 9

Now the value of i is incremented to 1 so i=5

When i=5 then i<num condition evaluate to false so the loop breaks. The next two print statement prints the values of even and odd. So

even = 6

odd = 9

Hence the output is:

Sum of Even Numbers: 6                                                                                                           Sum of Odd Numbers: 9  

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Positive use of the technology before the pandemic.
Nana76 [90]

Answer:

Positive use of the technology before the pandemic. Is to talk to relatives who live far away. Find a Cool Recipe and to be nice online.

Explanation:

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Entering the search criteria "B?" would yield which of the following results?
lutik1710 [3]

Answer:

D. Birmingham

Explanation:

Entering the search criteria "B", would yield Birmingham.

6 0
2 years ago
Code works, need help writing header file.
vovikov84 [41]

Answer:

kbfbnmcj hbx nmjn mz kjn  mj     hk hhhhhhgdhggbddddddbvgfcgfctrctgvhyubujbnjinkikmokimloplkmkojihgftrdesw3l,kmjinhuygtfrde4sw34drftyghuijokkkkkkkkkkkkkkkijjjjjjjkopl[[[[[koiju98hytttttttttttttuhiouhygdtrsgyuihkl;;ihugydtrcfbhjklioutrcgfbhjkloiuytdrhjukliuytrdgfhjkiouy7gfhjklpoiudtrkhjl;[poiughjbnm,;lkihuygtfvbnmjkiuytfgchvbnmkjlhuygfdc vbnhnjkygtdsfxghbjkiuhytrdgfhjuioytrdfgchbnmkloiuytfdfghjiouyyyyyyhjkpoi8u97t6rdghjuo0987hjklpo0i98uyghjbkopiuyhjbnkploiuhyjbnmkloiuhygbvjnmk,l;oipuhgbjkn mjhuygfvbnhjkiouuuukjopipkjmloiujoklm;okjm,kloiuhjnmkiuhjbkiuygfhuji8yghyugfvhjkjiuhygfhuijokpiuyt67u89poiuhygftduhjklphuytfrdesdtgyuhi;lkyuuuugij'[;;;;;;;;;;;;;;;;;;;;okpuuuutyyyyy[poiudtryuiop[;oiudtrruiooooooooytg[pl;oiuhygtfffkjjjjhugvcfxkml,;kjnhbgvchbjnk,lijuhygfcbvh nmmpoiugyhjb,m ./[poiuhbjnm,k;lijuytfrcgbvhkjlipouuuujipouuuukliouygkjliubhjkml

Explanation:

7 0
3 years ago
_______ are special incentives or excitement-building programs that encourage consumers to purchase a particular product, often
Damm [24]

Answer: sales promotion

Explanation:

Sales promotion are special incentives or excitement-building programs that encourage consumers to purchase a particular product, often used in conjunction with advertising or personal selling programs.

5 0
3 years ago
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