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nignag [31]
3 years ago
12

What is the maximum rate at which computers A and B can communicate, via router X? (your answer should be in Mbps)

Computers and Technology
1 answer:
eduard3 years ago
7 0
450Mbps on the 2.4GHz band and 1300Mbps on the 5GHz band
You might be interested in
Suppose you have an int variable called number. What Java expression produces the second-to-last digit of the number (the 10s pl
kobusy [5.1K]

Answer:

int second_to_last = (number/10)%10;

int third_to_last = (number/100)%10;

Explanation:

The first expression int second_to_last = (number/10)%10; first divide the number by ten and then get modulus by dividing by ten again which will then give the second to last digit.

Assuming number is 146 the second to last digit will be 4.

for the second expression int third_to_last = (number/100)%10; first divide the number by hundred and then get modulus by dividing by ten which will then give the third to last digit.

Assuming number is 4368 the third to last digit will be 3.

4 0
3 years ago
______ is a disadvantage of EDI.
Artist 52 [7]

Answer:The number of standards

Explanation:Electronic data interchange (EDI)  is the mechanism through which data is interchanged in the system electronically.It is mostly found in the business field for exchanging of data.

As EDI helps in making message accurate by decreasing the length and also has beneficial features of maintaining the security and increasing productivity ,hence these factor are not considered as the disadvantage .

Too many standard present in the EDI make the working complex by limiting the processing in the small business as compared with large organization.

 

6 0
2 years ago
Why might you want to save a downloaded file to your computer first instead of running it immediately?
sukhopar [10]

Answer:

Explanation:

Run: Choose Run when you only need the download once. Perhaps it’s a song or video you only plan to listen to or watch once. Another scenario might be an installation program that, when run, installs software on your machine in other, permanent locations. Once installed, you probably don’t need the installer again.

Save: When you want to keep whatever it is you’ve downloaded, choose Save. You can still run it, or whatever else you’d like to do with it, but you’ll need to do that yourself. You’ll also want to decide where, on your computer, to keep the file.

<em>Save and run: Use this option when you want to do both: save the file to a location you control, and then immediately run it. </em>

<em />

8 0
2 years ago
Write a program that reads numbers from a file (or allow user to input data) and creates an ordered binary tree. The program sho
IgorLugansk [536]

Answer:

See explaination

Explanation:

include<bits/stdc++.h>

using namespace std;

typedef struct Node

{

int data;

struct Node *left,*right;

}Node;

bool search(Node *root,int data)

{

if(root==NULL)

return false;

if(root->data==data)

return true;

queue<Node*> q;

q.push(root);

while(!q.empty())

{

Node *temp=q.front();

q.pop();

if(temp->data==data)

return true;

if(temp->left)

q.push(temp->left);

if(temp->right)

q.push(temp->right);

}

return false;

}

Node *insert(Node *root,int data)

{

if(root==NULL)

{

Node *temp=new Node();

temp->data=data;

temp->left=NULL;

temp->right=NULL;

return temp;

}

if(data < root->data)

root->left=insert(root->left,data);

if(data>root->data)

root->right=insert(root->right,data);

return root;

}

Node *get_smallest_element_right_subtree(Node *root)

{

while(root && root->left!=NULL)

root=root->left;

return root;

}

Node *delete_node(Node *root,int data)

{

if(root==NULL)

return root;

if(data < root->data)

root->left=delete_node(root->left,data);

else if(data > root->data)

root->right=delete_node(root->right,data);

else

{

if(root->left==NULL) //If right only presents means - delete the curr node and return right node

{

Node *temp=root->right;

free(root);

return temp;

}

else if(root->right==NULL) //If left only presents means - delete the curr node and return let node

{

Node *temp=root->left;

free(root);

return temp;

}

else

{

Node *temp=get_smallest_element_right_subtree(root->right);

root->data=temp->data;

root->right=delete_node(root->right,temp->data);

}

return root;

}

}

void inorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

cout<<root->data<<" ";

inorder(root->right);

}

}

void postorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

inorder(root->right);

cout<<root->data<<" ";

}

}

void preorder(Node *root)

{

if(root!=NULL)

{

cout<<root->data<<" ";

inorder(root->left);

inorder(root->right);

}

}

int main()

{

fstream f;

string filename;

cout<<"\n\n1 - Input through File ";

cout<<"\n\n2 - Input through your Hand";

int h;

cout<<"\n\n\nEnter Your Choice : ";

cin>>h;

Node *root=NULL; // Tree Declaration

if(h==1)

{

cout<<"\n\nEnter the Input File Name : ";

cin>>filename;

f.open(filename.c_str());

if(!f)

cout<<"\n\nError in Opening a file !";

else

{

cout<<"\n\nFile is Being Read ........";

string num;

int value;

int node=0;

while(f>> num)

{

value=stoi(num);

root=insert(root,value);

node++;

}

cout<<"\n\nTree has been successfully created with : "<<node<<" Nodes"<<endl;

}

}

if(h==2)

{

int y;

cout<<"\n\nEnter the Total No of Input :";

cin>>y;

int i=1,g;

while(i!=y+1)

{

cout<<"\n\nEnter Input "<<i<<" : ";

cin>>g;

root=insert(root,g);

i++;

}

cout<<"\n\nTree has been successfully created with : "<<y<<" Nodes"<<endl;

}

if(h>=3)

{

cout<<"\n\nInvalid Choice !!! ";

return 0;

}

int n=0;

while(n!=6)

{

cout<<"\n\n\n1 - Insert Element";

cout<<"\n\n2 - Remove Element";

cout<<"\n\n3 - Inorder (LNR) Display ";

cout<<"\n\n4 - Pre (NLR) Order Display";

cout<<"\n\n5 - Post (LRN) Order Display";

cout<<"\n\n6 - Quit";

cout<<"\n\nEnter Your Choice : ";

cin>>n;

switch(n)

{

case 1:

{

int k;

cout<<"\n\nEnter Element to insert : ";cin>>k;

root=insert(root,k);

cout<<"\n\nElement Sucessfully Inserted !!!!!";

break;

}

case 2:

{

int k;

cout<<"\n\nEnter Element to Remove : ";

cin>>k;

if(search(root,k))

{

root=delete_node(root,k);

cout<<"\n\nValue Successfully Deleted !!!";

}

else

cout<<"\n\n!!!!!!!!!!!!!!!!!!!! No Such Element !!!!!!!!!!!!!!!!!!!!!!";

break;

}

case 3:

{

cout<<"\n\nThe Elements (LNR) are : ";

inorder(root);

break;

}

case 4:

{

cout<<"\n\nThe Elements (NLR) are : ";

preorder(root);

break;

}

case 5:

{

cout<<"\n\nThe Elements (LRN) are : ";

postorder(root);

break;

}

case 6:

{

break;

}

}

}

cout<<"\n\nBye!!!! See You !!!"<<endl;

7 0
3 years ago
If you wanted to create a line of code that would add ten to the user’s current score, which code should you use?
Korvikt [17]

Answer:

choice c

Explanation:

score = score + 10

because the rest doesn't make since and score == score + 10 has an extra equal sign.

7 0
3 years ago
Read 2 more answers
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