What is the maximum rate at which computers A and B can communicate, via router X? (your answer should be in Mbps)

If a firm is set to use open-source software with which no one in the IT department is familiar, what should it do? fire the IT

Aleonysh [2.5K]

The most efficient thing to do would be to provide training as firing or doing nothing halts productivity indefinitely while training eventually will finish

7 0

2 years ago

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Given that Jamie worked 50 hours (Hours = 50) last week and earns $10.00 an hour (Rate = 10), how much did Jamie earn last week,

quester [9]

Answer:

Jamie earned (Total pay) $500.

Explanation:

We are given the following code:

If (Rate >=10) OR (Hours <=40) Then

TotalPay = Hours * Rate

Else

TotalPay = (Hours * Rate)+(Hours–40)*Rate*1.5

End If

Let us understand the code line by line:

The first line contains an if statement with 2 conditions:

i.e. 1st condition:

The rate is greater than or equal to 10

2nd condition:

Number of hours are lesser than or equal to 40.

There is OR between the two condition i.e. the statement next to if() statement will get executed if any one of them becomes true and else part will not be executed.

The next statement is:

TotalPay = Hours * Rate

It calculates the pay if any of the two conditions written earlier becomes true.

Next statement is else statement:

It will get executed given that the above if() statement becomes false.

Now, we are given that Jamie worked 50 hours last week and earns $10.00 an hour:

i.e.

Hours = 50

Rate = 10

Now, let get to the code execution.

The first condition is true i.e. Rate >= 10 (because Rate is 10 here)

So, the following statement will be used to calculate the Total pay:

TotalPay = Hours * Rate

and else part will not be executed.

TotalPay = 50 * 10 = $500

Jamie earned (Total pay) $500.

3 0

2 years ago

Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3

Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0

2 years ago

Why would students most likely need to collect data? Check all that apply

n200080 [17]

Well I would think all of them in some way. For the first one, students need to collect data (whether it’s mathematical, scientific, etc.) to answer a question. For the second one, they may need to know how much money is in there bank account or they may need to calculate a sale to order the item. For the third one, they may need statistical data to support a position. For the last one, a student could use technological data to be able to solve their problem sorting documents.

5 0

2 years ago

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Write a program that computes the minimum, maximum, average and standard deviation of the population over time for a borough (en

IrinaK [193]

Answer:

import pandas as pd #importing pandas library as pd

import matplotlib.pyplot as plt #importing matplotlib.pyplot as plt

pop=pd.read_csv('nycHistPop.csv') #reading the csv file

borough=input('Enter borough name:') #asking the user for borough namme

# image=input('Enter image name:')

# pop['Fraction']=pop[borough]/pop['Total']

# pop.plot(x='Year', y='Fraction')

print("Minimum population",pop[borough].min()) #printing the minimum population of borough

print("Maximum population",pop[borough].max()) #printing the maximum population of borough

print("Average population",pop[borough].mean()) #printing the average population of borough

print("Standard deviation",pop[borough].std()) #printing the standard deviation of borough

# fig=plt.gcf()

# fig.savefig(image)

Explanation:

4 0

2 years ago