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Alenkinab [10]
2 years ago
8

1.

Mathematics
1 answer:
MArishka [77]2 years ago
6 0

Answer:

x³+3x²-28x

Step-by-step explanation:

(x-4)(x-0)(x+7)

(x-4)(x)(x+7)

(x-4)(x+7)=(x²+3x-28)

(x²+3x-28)(x)=x³+3x²-28x

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What is the approximate distance between the points (1,-2) and (-9,3) on a coordinate grid
jeka57 [31]

<u>Answer</u>

5\sqrt{5} ≈ 11.1803398874989485


<u>Detailed Explanation </u>


We will be using the distance formula for this problem


\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}


Now, let's input the numbers into the formula.


\sqrt{\left(-9-1\right)^2+\left(3-\left(-2\right)\right)^2}


Solve.


Therefore, the distance between the two points is

5\sqrt{5} ≈ 11.1803398874989485

3 0
3 years ago
Read 2 more answers
(10.02)
ollegr [7]
<h2>Hello!</h2>

The answer is:

C. Cosine is negative in Quadrant III

<h2>Why?</h2>

Let's discard each given option in order to find the correct:

A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).

B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.

C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.

D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)

Have a nice day!

6 0
3 years ago
Graph the equation y-1=-3(x-3)
trapecia [35]

Answer:

y= -3x +10

the y-intercept is at 10 and then go 3 down one to the right

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Consider the function f(x)=x3+15x2+74x+120. If f(x)=0 for x=−6, for what other values of x is the function equal to 0? List the
jasenka [17]

Answer:

other x values are -5,-4

Step-by-step explanation:

f(x)=0 for x=−6

Apply synthetic division to get the quotient . using that we find other two values of x

-6                1           15             74          120

                   0          -6           - 54          -120                    

                  -------------------------------------------------

                    1           9             20         0

the quotient is x^2+9x+20=0

now factor the left hand side, product is 20 and sum is 9

x^2+9x+20=0\\(x+5)(x+4)=0\\x+5=0 , x=-5\\x+4=0, x=-4

So  other x values are -5,-4

8 0
3 years ago
Kim and Jay leave at the same time to travel 25 miles to the beach.Kim drives 9 miles in 12 minutes.Jay drives 10 miles in 15 mi
kow [346]
Jay will arrive before​ kim
4 0
3 years ago
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