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barxatty [35]
3 years ago
8

In 2003, the population of a city is 80,000 people, and is growing at a rate of 4% per year.

Mathematics
1 answer:
schepotkina [342]3 years ago
4 0
In thousands, the population can be modeled by
  P = 80*1.04^(t-2003)
where t is the year number

Finding answers to the questions can be done graphically.

a) In 2015, the population will be about 128,083.

b) The population will be 240,000 in 2031.


_____
a) p = 80,000*1.04^12
b) t = 2003+log(3)/log(1.04)

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3 years ago
X+y=180 <br> x=10y+48<br> (With Steps Plz)
ladessa [460]

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(168,12)

Step-by-step explanation:

Substitute x = 10y+48 in the first equation.

10y + 48 + y = 180 \\ 11y = 180 - 48 \\ 11y = 132 \\ y =  \frac{132}{11}  \\ y = 12

We have got the y-value. Our next goal is to find the x-value by <u>substituting</u><u> </u><u>y-value</u><u> </u><u>in</u><u> </u><u>any</u><u> </u><u>given</u><u> </u><u>equations</u><u>.</u><u />

For me, I will be substituting y = 12 in the first equation.

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<u>Answer</u><u> </u><u>Check</u>

Substitute both x-value and y-value in both equations.

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