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Bess [88]
1 year ago
6

Karl had planned to drive for 1023 hours on a certain day during his road trip. When he became sleepy, however, he decided to de

crease his driving time by 25% that day.
How long did Karl decide to drive that day?
Mathematics
1 answer:
netineya [11]1 year ago
8 0

Since Karl became sleepy and decided to decrease his driving time by 25%, he drove <u>767.25 hours</u> that day.

<h3>What is driving time?</h3>

Planned driving time is the estimated time that Karl planned to drive between two points or to one's destination.

The Actual driving time is the actual time that it took Karl to drive from one point to his destination.

Driving time can be estimated or calculated by dividing the distance by the speed.

<h3>Data and Calculations:</h3>

The planned driving hours on a certain day = 1,023 hours

Decrease in driving time = 25%

Percentage of hours Karl drove = 75% (100 - 25)

Hours drove that day = 767.25 hours (1,023 x 75%)

Thus, Karl drove <u>767.25 hours</u> that day.

Learn more about driving time at brainly.com/question/4931057

#SPJ1

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Answer:

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First we add those together.

31* + 43* = 74*

Then, we subtract that amount from 180*

180* - 74* = 106*

106* is the missing angle.

x106* - 31* = 75*

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~Hope this helps~

6 0
2 years ago
4/5 divided by 1/3 plus 1/5 minus 3/5
r-ruslan [8.4K]

Answer:

  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

Step-by-step explanation:

Considering the expression

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

Solution Steps:

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

as

\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}

so

=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}    

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}

join  \frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}

so

=\frac{4}{5\left(-\frac{1}{15}\right)}

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{4}{-5\cdot \frac{1}{15}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}

=-\frac{4}{5\cdot \frac{1}{15}}

\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}

so

=-\frac{4}{\frac{1}{3}}

\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}

so

=-\frac{12}{1}

\mathrm{Apply\:rule}\:\frac{a}{1}=a

=-12

Therefore

                  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

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Answer:

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Step-by-step explanation:

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azamat

Answer:

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Step-by-step explanation:

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If the units in the equation are in feet, it lef5t at a height of 7.4 feet (or meters, etc.).

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p(x) = - 0.013x2 + 0.02x + 7.4

When x, the time, = 0 [just before it leaves the pitcher's hand]

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