I think that it the secound one then the fourth one then the sixth one then the first one then the fifth one then third one the eighth one then the ninth one
Well i can't really help you in this since i do not know the cost of each calendar, but if you need the formula.
the cost of one calendar = x
so the total cost would be 200 times x (200x)
<span>solve the equation ax – c = bx + d for x:
1) Group the x terms together on the left: ax - bx - c = d
2) Group the constant terms together: ax - bx = c + d
3) factor out x: x(a - b) = c + d
4) Divide both sides of the equation by (a - b) to obtain a formula for x:
c+d
</span> x(a - b) = c + d => x = ---------
a-b
This shows that the given equation CAN be solved for x, but there is a restriction: a must NOT equal b, because if a-b = 0, we'd have division by zero (which is not defined).
Where is Victoria's solution? Please share it if you want to discuss this problem further. Thank you.
Answer: 63 degrees.
Step-by-step explanation:
7x + 4 +5x+3+2x+5=180 degrees
14x+12=180 -12 Degrees
14x / 14 = . 168 /14
x=12
5(12) +3
63