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Nostrana [21]
3 years ago
15

Maria started with $10. She has been saving $3 dollars each week to buy a softball bat. The amount of money Maria has depends on

how many weeks she has been saving. which expression represents Maria after x weeks? *
A) f(x) = 10x + 3



B) f(x) = 3x + 10



C) f(x) = 10x - 3



D) f(x) = 3x - 10
Mathematics
1 answer:
Mama L [17]3 years ago
3 0
The correct answer is b as she starts with 10 and keeps on added 3 dollars per week
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Before he left the house to go on a walk, Curtis played a video game. He started with O points, lost 8
erica [24]

Answer:

-22

Step-by-step explanation:

given= 0

lost= -8 times 3  =  -24

won= 4    -24+4=-20

lost= -2   -20-2=-22

Answer=-22

5 0
3 years ago
I need the mean, medium, and the mode for these numbers [4,10,11,15,16,16,18,19]​
iren [92.7K]

Hello here would be your answers:

mean: 13.6  

mediun: 15.5  

mode: 16

remember it like this

Mean is the average

Mode is the most often number

Range is when you subtract the smallest number from the largest number

Medium is the middle number when you line it up from the greatest to the least.

hope this helps!

7 0
3 years ago
The sum of two rational numbers is -8. if one of the is -8/17, find the other. plz help me ​
Vesnalui [34]
<h2>Step-by-step explanation:</h2>

-5/7 + x = -1

(-5+7x)/7 = -1

-5 + 7x = -7

7x = -2

<h2>x = -2/7</h2>

please change the digit as per ur QUESTION

6 0
2 years ago
Read 2 more answers
Assuming that the population is normally​ distributed, construct a 9090​% confidence interval for the population mean for each o
jasenka [17]

Given:

Set A: 1 4 4 4 5 5 5 8

Mean: 4.5

Standard dev: 1.9

 

Set B:

Mean: 4.5

Standard dev: 2.45

 

% =  90 

Set A:

Standard Error, SE = s/ √n =    1.9/√8 = 0.67  

Degrees of freedom = n - 1 =   8 -1 =  7   

t- score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.67 = 1.272685913

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.272685913 = 3.23

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.272685913 = 5.77

The 90% confidence interval is [3.23, 5.77]

 

Set B:

Standard Error, SE = s/ √n =    2.45/√8 = 0.87  

Degrees of freedom = n - 1 =   8 -1 = 7   

t- Score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.87 = 1.641094994

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.641094994 = 2.86

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.641094994 = 6.14

The 90% confidence interval is [2.86, 6.14]

 

<span>We can obviously see that sample B has more variation in the scores than sample A. The fact that the standard deviation is 2.45 for B and 1.9 for A). Therefore, they yield dissimilar confidence intervals even though they have the same mean and range.</span>

6 0
3 years ago
A ship leaves port on a bearing of 34.0 and travels 10.4 mi. the ship then turns due east and travels 4.6mi. how far is the ship
Natasha2012 [34]
A bearing of 34° corresponds to corresponding angle of θ=90-34=56°
The (x,y) values for the position of the ship after completing its first heading are:
x=(10.4cos 56)
y=(10.4sin56)

The trigonometric angle for θ=90-90=0
The (x,y) values for the postion of the ship after completing the second bearing is:
x=(10.4 cos56)+(4.6cos0)≈10.4 mi
y=(10.4sin56)+(4.6sin0)≈8.6mi

the distance from the port will therefore be:
d=√(10.4²+8.6²)≈13.5 miles

It trigonometric angles is:
θ=arctan(y/x)
θ=arctan(8.6/10.4)
θ≈39.6°
Thus the bearing angle is:
90-39.6=50.4°
6 0
3 years ago
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