The least common multiple of 6 and 21 is 42.
The measure of ∠ACB will be 110°
<u><em>Explanation</em></u>
According to the diagram below, and are the perpendicular bisectors of and respectively and they intersect side at points and respectively.
So, and
Now, <u>according to the postulate</u>, ΔAPE and ΔCPE are congruent each other. Also, ΔCFQ and ΔBFQ are congruent to each other.
That means, ∠PCE = ∠PAE and ∠FCQ = ∠FBQ
As ∠CPQ = 78° , so ∠PCE + ∠PAE = 78° or, ∠PCE = ° and as ∠CQP = 62° , so ∠FCQ + ∠FBQ = 62° or, ∠FCQ = °
Now, in triangle CPQ, ∠PCQ = 180°-(78° + 62°) = 180° - 140° = 40°
Thus, ∠ACB = ∠PCE + ∠PCQ + ∠FCQ = 39° + 40° + 31° = 110°
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Answer:
there will be 1 person = the winner at round 10, and at round 9 there will be 5 it goes down by fifteen every time
Step-by-step explanation:
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