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Alekssandra [29.7K]
1 year ago
11

Let x be a continuous random variable having cumulative distribution function f. define the ran- dom variable y by y =f(x). show

that y is uniformly distributed over (0, 1).
Mathematics
1 answer:
DochEvi [55]1 year ago
7 0

Given that F is a distribution function then it is going to be said to be non decreasing.

<h3>How to define the random variable</h3>

Let Y = F(x)

Then we have a distribution function that we can define to be

Gy(Y) = P(Y≤y) = P[F(X)≤y]

=  P[x≤F⁻¹(y)]

The inverse is said to exist given that the value F is non decreasing and it is also said to be continuous.

Such that Gy(Y)  = F[F⁻¹(y)]

then we have to see f to be the distribution of x

Gy(Y) = y

The PDF of Y is denoted as Y = F(X)

then we would have

d/dy [Gy(Y)] = 1

Given that F is a df, then the value of the distribution function would always be 0, 1.

gy(y) would then have to be 1

0 ≤ y ≤ 1

This tells us that F(X) is a uniform variate of 0,1.

Read more on cumulative distribution function here:

brainly.com/question/14100876

#SPJ1

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7 0
4 years ago
1. The midpoint of GH is (-2,3), and its endpoints are G (g,4) and H (-2,h). What are the values of g and h
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Answer:(g,h)=(-2,2)

Step-by-step explanation:

Given

Midpoint is (-2,3)

Endpoints are G(g,4) and H(-2,h)

Mid point of any two point is given by

x=\frac{x_1+x_2}{2}

and y=\frac{y_1+y_2}{2}

So,-2=\frac{g+(-2)}{2}

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Also

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