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dimaraw [331]
4 years ago
8

Write equations for the horizontal and vertical lines passing through the point , (4,5).

Mathematics
1 answer:
yan [13]4 years ago
4 0

Answer:

Answer is below

Step-by-step explanation:

The equation for the horizontal line is x = 4. The equation for the vertical line is y = 5.

I graphed the lines on the graph below to show you that they intersect at the point (4,5).

If these answers are correct, please make me Brainliest!

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What are the intercepts of the line 2x + 4y = 12?
Triss [41]
For x-intercepts, you plug 0 for y and solve for x, and vice versa for y-intercepts.

X: 2X+4(0)= 12
2x= 12
12/2= 6 so the x intercept is 6. 

Y: 2(0)+4Y=12
4y= 12
12/4= 3 so the y intercept is 3.

Your answer is B. <span>x-intercept: 6; y-intercept: 3</span>
8 0
3 years ago
Read 2 more answers
The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

                                               = 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

7 0
4 years ago
Read 2 more answers
Let u = &lt;-9, 4&gt;, v = &lt;8, -5&gt;. Find u - v. <br> URGENT
Pie

To subtract vectors, you simply have to subtract correspondent coordinates.

So, if you have

u = \langle u_1,\ u_2,\ldots u_n\rangle ,\quad v = \langle v_1,\ v_2,\ldots v_n\rangle

the subtraction is simply

u-v = \langle u_1-v_1,\ u_2-v_2,\ldots u_n-v_n\rangle

So, in your case, we have

\langle-9,4\rangle-\langle 8,-5\rangle=\langle -9-8, 4+5\rangle=\langle -17,9\rangle

3 0
3 years ago
Dolve the equation <br> 11q-6=3q+8q
Amanda [17]

Answer:

no solution

Step-by-step explanation:

Simplifying

11q + -6 = 3q + 8q

Reorder the terms:

-6 + 11q = 3q + 8q

Combine like terms: 3q + 8q = 11q

-6 + 11q = 11q

Add '-11q' to each side of the equation.

-6 + 11q + -11q = 11q + -11q

Combine like terms: 11q + -11q = 0

-6 + 0 = 11q + -11q

-6 = 11q + -11q

Combine like terms: 11q + -11q = 0

-6 = 0

Solving

-6 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

6 0
4 years ago
How can you do this
ololo11 [35]

You add up all of the sides and the numbers that are there you pretend that they are on the other side and just add all of them up correctly and you will get your answer.


3 0
3 years ago
Read 2 more answers
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