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antoniya [11.8K]
2 years ago
7

(c) a farm brings 15 tons of watermelon to market. find a 90% confidence interval for the population mean cash value of this cro

p (in dollars). what is the margin of error (in dollars)? hint: 1 ton is 2000 pounds. (for each answer, enter a number. round your answers to two decimal places.)
Mathematics
1 answer:
Nina [5.8K]2 years ago
7 0

Answer:

First we need to name some of the variables we are given:n = 38 the sample sizex = 6.88 the sample mean = 1.86 the population standard deviationWe need to find a 90% confidence interval for the mean price per 100 lbs of watermelon: = 1-.90 = .10/2 = .05z(/2) = -1.64-z(/2) = 1.64This can give us a probability expression:P(-1.645 < z < 1.645) = .90The margin of error is calculated with the formula: E = z(/2)(/√n)E = 1.645(1.86/√38) = $.4963(300) = $148.89   Then to calculate the upper and lower limit we add and subtract E from x:lower limit = 6.88 - .4963 = $7.38(300) = $2214upper limit = 6.88 + .4963 = $6.38(300) = $1914Note: We multiply the E, upper and lower limits by 300 because 15 tons is 30000lbs and we need the price per 100 lbs, so we divide 30000/100 and get 300.

Step-by-step explanation:

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