Answer:
25X + 25Y = 1700
25X + 100Y = 3200
Step-by-step explanation:
Given that the principal of a high school spent $1700 for X desk and Y chairs at $25 each. Then, the equation will be
25X + 25Y = 1700 ....... (1)
If he had bought half the number of desk in twice the number of chairs he would have spent 1600. That is
25(X/2) + 25(2Y) = 1600
25X/2 + 50Y = 1600
Find the LCM and cross multiply
25X + 100Y = 3200 ........(2)
Using the fundamental counting theorem, we have that:
- 648 different area codes are possible with this rule.
- There are 6,480,000,000 possible 10-digit phone numbers.
- The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.
For the area code:
- 8 options for the first digit.
- 9 options for the second and third.
Thus:

648 different area codes are possible with this rule.
For the number of 10-digit phone numbers:
- 7 digits, each with 10 options.
- 648 different area codes.
Then

There are 6,480,000,000 possible 10-digit phone numbers.
The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
A similar problem is given at brainly.com/question/24067651
Answer:
Step-by-step explanation:
35
The point of intersection is the point where lines intersect.
<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>
<em />
Given
<em />
<em> --- the number of lines</em>
<em />
<em> --- no three lines are concurrent</em>
<em />
When no three line are concurrent, it means that no three lines meet at the same point.
<u>So, the sequence of intersection is:</u>
- <em>0 intersection for 1 line</em>
- <em>1 intersection for 2 lines</em>
- <em>3 intersections for 3 lines</em>
- <em>6 intersections for 4 lines</em>
<em />
Following the above sequence, the number of intersections for n lines is:

In this case, 
So, we have:




<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>
<em />
Read more about lines of intersections at:
brainly.com/question/22368617
1157/500 is as simple it can be as a fraction .