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Reptile [31]
2 years ago
5

Okay so this is super tricky, there is a riddle on my math quiz. Yk for extra credit and its 25% of my grade, according to Mr. W

ells.
If you have 1 cow that is worth $2,500 and 2 cats worth $100. But one dog is worth $7000, what would the outcome be if there was only 1 of each animal? Hint: It could be division or multiplication.
A. 2 cats and one dog
B. 1 cow and 1 dog
C. $600 for each animal
D. If you think its none of these listed, you may write your own!
Note: this makes no sense whatsoever, so please help. Mr. Wells is a good teacher, but this question is hard
Mathematics
1 answer:
nlexa [21]2 years ago
3 0

If there was just one of each animal, the outcome would be that of 1 cow and 1 dog.

Option(B) is correct.

The average cost, or how much it generally costs to produce a unit, can be discovered using the cost function.

If you own two cats worth $100 each and a cow worth $2,500. One dog, though, is worth $7000.

Cost of 1 cow = $2500

Cost of 2 cats = $100

Thus, cost of 1 cat = $100/2 = $50

Cost of 1 dog = $7000

If there was only 1 of each animal, total cost = $(2500+50+7000) = $9550.

This outcome resembles the situation of having 1 cow and 1 dog.

Learn more about cost here:

brainly.com/question/25109150

#SPJ1

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Answer:

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Step-by-step explanation:

The amortization period in months is:

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The payment for monthly mortgage formula would be:

E=\frac{C*r}{1-(1+r)^{-n}}

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n is the period, in months, which is 360

Substituting, we get our answer:

E=\frac{C*r}{1-(1+r)^{-n}}\\E=\frac{150,000*0.004375}{1-(1+0.004375)^{-360}}\\E=\frac{656.25}{1-(1.004375)^{-360}}\\E=\frac{656.25}{0.7923}\\E=828.31

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Answer:

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Step-by-step explanation:

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The equation that can be used to find the missing number is 96 - 12n = 3 + n

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