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ella [17]
3 years ago
7

The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units? (1 point)

Mathematics
1 answer:
zlopas [31]3 years ago
7 0
The first choice is correct. No, the rectangle cannot have x=60 and y=11 because x=48+2y.

Perimeter is x=2w+2y. Therefore x=2(24)+2(11) which equals 70 not 60.
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If x = 4, y = 3, z = -5, then evaluate: z - z + x - y
deff fn [24]
I got -15 as the answer, hope it works
7 0
3 years ago
Read 2 more answers
3<br> Which expression is closest in value to 5.66?
Free_Kalibri [48]

Let's consider the standard and usually used value of irrational numbers given in the question.

  • It is asked to see which is closed to 5.66

So, let's see the options:

A) GiveN:

\dfrac{\pi}{2}  + \pi

Let consider π = 3.14

\dfrac{3.14}{2}  + 3.14

1.57 + 3.14

4.71 \: (approx.)

B) GiveN:

2\pi - 1

Here also, let's consider the value be 3.14

2 \times 3.14 - 1

6.28 - 1

5.28  \: (approx.)

C) GiveN:

4 \sqrt{2}

Let's consider the value of √2 be 1.414

4 \times 1.414

5.6516  \: (approx.)

D) GiveN:

8 -  \sqrt{3}

Let's consider the value of √3 be 1.732

8 - 1.732

6.268 \: (approx.)

So, we can see that we have got the approximate value of all the numericals, and the closest to 5.66 is 5.6516 which is the answer of Option C.

So, Correct answer is C

#CarryOnLearning

<u>━━━━━━━━━━━━━━━━━━━━</u>

6 0
3 years ago
• The shortest side of a triangle is 8 centimeters long. The longest side is 8 cm longer than the
gizmo_the_mogwai [7]
The shortest side is 9, longest is 17 of the triangle IS NOT a 90 degree triangle
5 0
3 years ago
The average weight of the class of 35 students was 45 KG. with the admission of a new student the average weight came down to 44
melamori03 [73]

The weight of the new student is 27 kg.

Average weight

= total weight ÷total number of students

<h3>1) Define variables</h3>

Let the total weight of the 35 students be y kg and the weight of the new student be x kg.

<h3>2) Find the total weight of the 35 students</h3>

<u>45 =  \frac{y}{35}</u>

y= 35(45)

y= 1575 kg

<h3>3) Write an expression for average weight of students after the addition of the new student</h3>

New total number of students

= 35 +1

= 36

Total weight

= total weight of 35 students +weight of new students

= y +x

44.5  =  \frac{y + x}{36}

<h3>4) Substitute the value of y</h3>

44.5 =  \frac{1575 + x}{36}

<h3>5) Solve for x</h3>

36(44.5)= 1575 +x

1602= x +1575

<em>Subtract 1575 from both sides:</em>

x= 1602 -1575

x= 27

Thus, the weight of the new student is 27 kg.

7 0
3 years ago
URGENT!!! plz help will give brainlist question is in photo
grandymaker [24]
Answer:

x = 3

Explanation:

15x + 5 + 22x + 4 + 60 = 180

37x + 69 = 180

37x = 111

x = 3
3 0
3 years ago
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