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krok68 [10]
2 years ago
10

What is the indication when a student conducting an electronic search of the literature is simultaneously using two databases, p

ubmed and ebsco, which generate more than 2000 citations?
Computers and Technology
1 answer:
aivan3 [116]2 years ago
5 0

Generate more than 2000 citations is The keywords were not sufficiently narrowed.

<h3>Why utilize PubMed as a database?</h3>

PubMed is the standard database that is used in the healthcare profession. It has the ability to link to full-text articles, provides advance researching including filtering and superior queries and links to related articles.

<h3>What are the restrictions of PubMed?</h3>

The newest articles in PubMed may not yet be indexed for MEDLINE. There is a short lag time (a few days to many weeks) between when authorities enter the PubMed database and when they are described with MeSH terms. An article you require is not indexed for MEDLINE

To learn more about PubMed , refer

brainly.com/question/602370

#SPJ4

A. There has been a great deal of research in this area.

B. CINAHL and MEDLINE duplicate the literature.

C. The keywords were not sufficiently narrowed.

D. A third database is necessary to limit the search.

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Read 2 more answers
Create an application containing an array that stores 10 integers. The application should call five methods that in turn (1) dis
tensa zangetsu [6.8K]

Answer:

  1.     public class Main {
  2.    public static void main(String[] args) {
  3.        int myArray[] = {3, 7, 2, 5, 9,11, 24, 6, 10, 12};
  4.        int myArray2 [] = {1, 2, 3, 4 ,5};
  5.        displayValue(myArray);
  6.        reverseDisplay(myArray);
  7.        displaySum(myArray);
  8.        displayLess(myArray, 10);
  9.        displayHighAvg(myArray);
  10.        displayBoth(myArray, myArray2);
  11.    }
  12.    public static void displayValue(int arr[]){
  13.        for(int i = 0; i < arr.length; i++){
  14.            System.out.print(arr[i] + " ");
  15.        }
  16.        System.out.println();
  17.    }
  18.    public static void reverseDisplay(int arr[]){
  19.        for(int i = arr.length-1; i >= 0; i--){
  20.            System.out.print(arr[i] + " ");
  21.        }
  22.        System.out.println();
  23.    }
  24.    public static void displaySum(int arr[]){
  25.        int sum = 0;
  26.        for(int i = 0; i < arr.length; i++){
  27.            sum += arr[i];
  28.        }
  29.        System.out.println(sum);
  30.    }
  31.    public static void displayLess(int arr[], int limit){
  32.        for(int i = 0; i < arr.length; i++){
  33.            if(arr[i] < limit){
  34.                System.out.print(arr[i] + " ");
  35.            }
  36.        }
  37.        System.out.println();
  38.    }
  39.    public static void displayHighAvg(int arr[]){
  40.        int sum = 0;
  41.        for(int i = 0; i < arr.length; i++){
  42.            sum += arr[i];
  43.        }
  44.        double avg = sum / arr.length;
  45.        for(int i = 0; i < arr.length; i++){
  46.            if(arr[i] > avg){
  47.                System.out.print(arr[i] + " ");
  48.            }
  49.        }
  50.        System.out.println();
  51.    }
  52.    public static void displayBoth(int arr1[], int arr2 []){
  53.        for(int i = 0; i < arr2.length; i++){
  54.            for(int j = 0; j < arr1.length; j++){
  55.                if(arr1[j] == arr2[i]){
  56.                    System.out.print(arr1[j] + " ");
  57.                }
  58.            }
  59.        }
  60.        System.out.println();
  61.    }
  62. }

Explanation:

There are five methods written to solve all the problems stated in the question.

Method 1 : displayValue    (Line 15 - 21)

This is the method that take one input array and use the print() method to display the all the elements in the array.

Method 2: reverseDisplay (Line 23 - 26)

This method will take one input array and print the value in the reverse order. We just need to start with the last index when running the for-loop to print the value.

Method 3: displaySum (Line 31 - 37)

This method will take one input array and use a for-loop to calculate the total of the values in the array.

Method 4: displayLess (Line 39 - 47)

This method will take one two inputs, a array and a limit. We use the limit as the condition to check if any value less than the limit, then the value will only be printed.

Method 5: displayHighAvg (Line 50 - 64)

This method will take one input array and calculate the average. The average will be used to check if any element in the array higher than it, then the value will only be printed.

Method 6: displayBoth  (Line 66 - 75)

This method will take two input arrays and compare both of them to find out if any value appears in both input arrays and print it out.

3 0
3 years ago
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