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Darina [25.2K]
3 years ago
8

Implement a metho d to nd the k-th largest element in an array of size N using a minimum priority queue (MinPQ). Assume that the

MinPQ class has a constructor that takes a single integer representing its maximum size, a insert(), a min(), a delMin(), an isEmpty(), and size() metho ds. The MinPQ do es not resize (to preserve O(logn p erformance). You may not imp ort any packages. Creating additional help er metho ds is ne but you should provide a one line comment that indicates their purp ose.
Computers and Technology
1 answer:
diamong [38]3 years ago
3 0

Sorry don't understand spanish,I am sure you can get it wrong,for crying out loud you people get checks for coming to United States

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Assume that a boolean variable isQuadrilateral has been declared, and that another variable, numberOfSides has been declared and
egoroff_w [7]

Answer:

# The below code is in python programming language.

if(numberOfSides==4): #check the value number of slide is equal to 4 or not.

   isQuadrilateral=True # assignment statement for if condition

else:

  isQuadrilateral=False # assignment statement for else condition

Explanation:

The above code is in python language in which--

  • The first lines are the "if" condition which checks the value of "numberofslides" variable.
  • The second lines assign true in "isQuadrilateral" variable if "if" condition is true.
  • The third line is for "else" statement that executes when the "if" condition is false.
  • The fourth line is for "else" statement which assigns the value false to the numberofslides variables.
4 0
4 years ago
g Given a 5 by 5 matrix of all positive values, write a program to find and display the greatest product of the 2 adjacent value
Rom4ik [11]

Answer:

Check the explanation

Explanation:

% iterate through each column (outer loop) , then iterate rows-1 (inner loop)

%take product of adjacent rows

mat = input('enter 5 by 5 matrix : ');

[R,C] = size(mat);

max_prod =0;

for c =[1:C]

for r=[1:(R-1)]

temp = mat(r,c)*mat((r+1),c);

if max_prod<temp

max_prod=temp;

end

end

end

fprintf('Greatest product : %i\n', max_prod)

Kindly check the output in the attached image below.

7 0
3 years ago
Calculate how many different pixel colours could be formed if one of the bytes gives the intensity of the red colour, one of the
Elena L [17]

Answer: The three RGB colors are each 8-bits (possible values [0.. 255], 2 to the power of 8 = 256) of each of Red, Green, and Blue. The three 8-bit RGB components can create up to 256×256×256 = 16.7 million possible RGB color combinations, called 24-bit "color".

Explanation:

6 0
3 years ago
Make The PYTHON Code<br><br> print first 3 character of a string - given "Seattle" expected "Sea"
vlada-n [284]

This program uses a conditional to determine if seafood is safe to consume.

IF (seafood = "mollusk" OR daysFrozen ≥ 7) { rating ← "safe" } ELSE { rating ← "unsafe" }

In which situations will rating be "safe"?

️Note that there may be multiple answers to this question.

Choose all answers that apply:Choose all answers that apply:

1. When sea food is mollusk and day frozen is 1

2.When sea food is mollusk and day froze is 9

3. When see food salmon and day frozen is 7

<em>Did that help?</em>

6 0
2 years ago
Write a class with a constructor that accepts a String object as its argument. The class should have a method that returns the n
mote1985 [20]

Answer:

import java.util.Scanner;

public class VowelsAndConsonantsDemo {

   /**

   The printMenu methods displays a menu to the user

    */

   public static void printMenu() {

       System.out.println("Please select an option: ");

       System.out.println();

       System.out.print("a. Count the number of vowels in the string.\n"

               + "b. Count the number of consonants in the string.\n"

               + "c. Count both the vowels and consonants in the string.\n"

               + "d. Enter another string.\n"

               + "e. Exit the program\n");

   }

   public static void main(String[] args) {

       String input;      // to hold the user's input

       String option;     // to hold the user's input

       char choice;       // to hold a single character

       char exit;         // user chooses 'e' to exit the program

       char letter;       //the Y or N from the user's decision to exit

       // create a Scanner object to read keyboard input.

       //  Scanner keyboard = new Scanner(System.in);

       Scanner keyboard;

       do {

           keyboard = new Scanner(System.in);

           // ask user to enter string

           System.out.print("Enter a string: ");

           input = keyboard.nextLine();

           input = input.toLowerCase();

           System.out.println();

           printMenu();

           option = keyboard.nextLine();

           choice = option.charAt(0);

           VowelsAndConsonants words = new VowelsAndConsonants(input);

           switch (choice) {

               case 'a':

               case 'A':

                   System.out.println("Number of Vowels: " + words.getVowels());

                   break;

               case 'b':

               case 'B':

                   System.out.println("Number of Consonants: " + words.getConsonants());

                   break;

               case 'c':

               case 'C':

                   System.out.println("Number of Vowels & Consonants: " + words.getConsonants()

                           + words.getVowels());

                   break;

               case 'd':

               case 'D':

                   System.out.println("Enter a string: ");

                   break;

               case 'e':

               case 'E':

                   System.exit(0);

                   break;

               default:

                   System.out.println("You did not enter a valid choice.");

           }

           //

           // keyboard.nextLine();    //consumes the new line character after the choice

           // String answer = keyboard.nextLine();

           // letter = answer.charAt(0);

       } while (true);

   }

}

4 0
3 years ago
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