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just olya [345]
3 years ago
10

Application programmers specialize in developing system software such as operating systems, device drivers, security modules, an

d communications software.?
a. True
b. False
Computers and Technology
1 answer:
Elina [12.6K]3 years ago
8 0
False, System Architects do this. App Programmers make apps for the user to use.
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Suppose company A wants to develop a program that duplicates the functionality of a programm by company B. Describe how company
kompoz [17]
The design of the software is covered by copy right unless it is open sourced or is a very common interface. They would need to come up with their own design and way of solving the problem to have a solution that was not copyrighted.
5 0
4 years ago
1. Write programming code in C++ for school-based grading system. The program should accept the Subject and the number of studen
satela [25.4K]

In this program, I am using the school-based grading system and the program should accept the subject and the number of students.

Program approach:-

  • Using the necessary header file.
  • Using the standard I/O namespace function.
  • Define the main function.
  • Declare the variable.
  • Display enter obtain marks in 5 subjects.
  • Return the value.

Program:-

//header file

#include<iostream>

//using namespace

using namespace std;

//main method

int main()

{

//declare variable

  int j;

  float mark, sum=0, a;

//display enter obtain marks in 5 subjects

  cout<<"Enter Marks obtained in 5 Subjects: ";

  for(j=0; j<5; j++)

  {

      cin>>mark;

      sum = sum+mark;

  }

  a = sum/5;

//display grade

  cout<<"\nGrade = ";

  if(a>=91 && a<=100)

//display a1

      cout<<"a1";

  else if(a>=81 && a<91)

//display a2

      cout<<"a2";

  else if(a>=71 && a<81)

      cout<<"b1";

  else if(a>=61 && a<71)

      cout<<"b2";

  else if(a>=51 && a<61)

//display c1

      cout<<"c1";

  else if(a>=41 && a<51)

//display c2

      cout<<"c2";

  else if(a>=33 && a<41)

//display d

      cout<<"d";

  else if(a>=21 && a<33)

//display e1

      cout<<"e1";

  else if(a>=0 && a<21)

//display e2

      cout<<"e2";

  else

//display invalid

      cout<<"Invalid!";

  cout<<endl;

//return the value

  return 0;

}

Learn more grading system

brainly.com/question/24298916

7 0
3 years ago
________ is a condition in which information inflow exceeds an individual's processing capacity. Select one: a. Information over
In-s [12.5K]

Answer:

Option a is the correct answer.

Explanation:

  • The information overflow is a state where the coming information will be more in comparison with processing information.
  • For example, if there is limited space and any user has more luggage to keep on that space, then we can say that the luggage is overflow.
  • So when the information is more and the processing capacity is less then we can say it information overflow condition and it is also asked by the above question. Hence option a is the correct answer.
  • While the other is not because:- option b, c and d states some information statements which do not come in any information condition.
6 0
3 years ago
Compare the two types of formatting that IDE devices must go through. What is the primary difference between the two?
Andrei [34K]
A quick format<span> changes the file system while the </span>full format<span> also checks the </span>drive for bad sectors.  <span>The scan for bad sectors is the reason why the Full </span>format<span> takes twice as long as the </span>Quick format<span>. If you choose the </span>Quick format<span> option, the </span>format<span> removes address files from the partition, but does not scan the disk for bad sectors.</span>
7 0
3 years ago
Read 2 more answers
Assume that name is a variable of type string that has been assigned a value . write an expression whose value is the first char
4vir4ik [10]

For the first question, you would just add the parenthesis to the string mutation1:

String word = "sadly";

String mutation1 = "(" + word + ")";

For the second you need the method substring from the String class:

It is defined as String.substring(begining, ending);

String name = "Smith";

String firstCharacter = name.substring(0, 1);

0 is considered the beginning of the string, then you get the next 1 characters.

7 0
3 years ago
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