Answer:
I think the calculation answer will be 9,999,811,112
There are (5 C 1) = 5! / (5 - 1)! = 5 ways of drawing a red marble, and (11 C 1) = 11! / (11 - 1)! = 11 ways of drawing any marble, so that the probability of drawing a red marble is 5/11.
After putting back the first marble, the probability of drawing another red is again 5/11.
So the probability of drawing 2 red marbles with replacement is (5/11)² = 25/121.
Answer:
x=wp/5
Step-by-step explanation:
x² + 2x + 2
Step-by-step explanation:
(F + G)(x)
= F(x) + G(x)
= 2x + x² + 2
= x² + 2x + 2
There are 13 clubs in a standard 52 card deck. The first time you draw a club the odds of doing it are
13/52 = 1/4
The second time you draw a club, the number of clubs have gone down by 1 and the number of cards in the deck have also gone down by 1.
So this time the odds are12/51
The probability of both happening, one after the other without replacement is
1/4 * 12/51 = (1*12)/(4*51) = 12/204 = 3/51 = 1/17
1/17 = 0.0588